34o & 56o To find it you need to set up some algebraic equations: Let x be one angle and y the other. So x=(1/2)*y + 6 (one-half of the other angle plus 6 degrees) Since the angles are complimentary, they must add to 90o So, Y + (1/2)*Y + 6 = 90 Solving for Y = 56o and X = 90 - Y or 90-56 = 34o
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the larger angle is 60 and the smaller angle is 30.complimentary angles are 2 angles forming 90 degrees.
Two angles that add up to a right angle are called complementary angles.Let the larger angle be x degrees, then the smallest angle is x - 15 degrees. So we have:x + (x - 15) = 902x - 15 = 902x - 15 + 15 = 90 + 152x = 1052x/2 = 105/2x = 52.5x - 15 = 52.5 - 15 = 37.5Thus, the complementary angles are 37.5 and 52.5 degrees.
The question is contradictory as complimentary angles are defined as having a sum of 90 degrees.
the two acute angles have a sum of 90. If the ratio is 4:1, then there are five units to split. Divide the 90 degrees by 5.90/5 = 1818 * 4 = 72So the larger angle has a measure of 72 degrees and the smaller angle is 18 degrees.
We know complementary means they add up to 90 degrees. Let x = small angle Therefore 5x = bigger angle x + 5x = 90 6x = 90 x = 90/6 x = 15 Therefore the smaller angle is 15 degrees and the bigger angle is 75 degrees (15 x 5).