34o & 56o To find it you need to set up some algebraic equations: Let x be one angle and y the other. So x=(1/2)*y + 6 (one-half of the other angle plus 6 degrees) Since the angles are complimentary, they must add to 90o So, Y + (1/2)*Y + 6 = 90 Solving for Y = 56o and X = 90 - Y or 90-56 = 34o
the larger angle is 60 and the smaller angle is 30.complimentary angles are 2 angles forming 90 degrees.
Two angles that add up to a right angle are called complementary angles.Let the larger angle be x degrees, then the smallest angle is x - 15 degrees. So we have:x + (x - 15) = 902x - 15 = 902x - 15 + 15 = 90 + 152x = 1052x/2 = 105/2x = 52.5x - 15 = 52.5 - 15 = 37.5Thus, the complementary angles are 37.5 and 52.5 degrees.
The question is contradictory as complimentary angles are defined as having a sum of 90 degrees.
the two acute angles have a sum of 90. If the ratio is 4:1, then there are five units to split. Divide the 90 degrees by 5.90/5 = 1818 * 4 = 72So the larger angle has a measure of 72 degrees and the smaller angle is 18 degrees.
We know complementary means they add up to 90 degrees. Let x = small angle Therefore 5x = bigger angle x + 5x = 90 6x = 90 x = 90/6 x = 15 Therefore the smaller angle is 15 degrees and the bigger angle is 75 degrees (15 x 5).
Complementary angles are angles that add up to 90 degrees. If the smaller angle is x, the larger is 5x, so 6x = 90. X equals 15, and the larger angle measures 75 degrees.
the larger angle is 60 and the smaller angle is 30.complimentary angles are 2 angles forming 90 degrees.
Two angles that add up to a right angle are called complementary angles.Let the larger angle be x degrees, then the smallest angle is x - 15 degrees. So we have:x + (x - 15) = 902x - 15 = 902x - 15 + 15 = 90 + 152x = 1052x/2 = 105/2x = 52.5x - 15 = 52.5 - 15 = 37.5Thus, the complementary angles are 37.5 and 52.5 degrees.
The question is contradictory as complimentary angles are defined as having a sum of 90 degrees.
Complementary angles total 90 degrees so smaller is 90/5 ie 18 and larger 72.
For any given angle, its supplementary angle is 90 degrees larger than its complementary angle.
this is what i have: X= 6+(90-X)+2(90-X) and i got 42 degrees?
The smaller angle is 20 degrees and the larger is 70 degrees. Complementary angles total 90 degrees. Let's call the smaller angle A. The other angle is 3A + 10. The sum of both angles is 90, so 4A +10 = 90, 4A = 80, A = 20. The larger angle is 3(20) + 10 = 70.
Suppose the larger angle is x degrees. Then the smaller angle is x - 2 degrees, and so they sum to 2x - 28 degrees. The two angles are complementary, so 2x - 28 = 90 is 2x = 90 + 28 = 118 so that x = 118/2 = 59 degrees and then x - 29 = 59 - 28 = 31 degrees. The two angles are 59 and 31 degrees.
let x=smaller angle2x-6=larger anglex+(2x-6)=903x-6=903x=96x=322x-6=58
It is: 72 degrees
Complementary angles add up to 90 degrees. Smaller angle: x Larger angle: 2x 2x+x=90 3x=90 x=30 The smaller angle is 30 degrees.