#include<stdio.h>
void transpose(int a[50][50]);
void main()
{
int a[50][50],b[50][50],m,n,i,j;
scanf("%d",&m,&n);
for(i=0;i<m;i++)
{
for(j=0;j<n;j++)
{
scanf("%d",&a[i][j]);
}
}
for(i=0;i<n;i++)
{
for(j=0;j<m;j++)
{
scanf("%d",&b[i][j]);
}
}
transpose(a,b,m,n)
void transpose(int a[50][50],int b[50][50],int m,int n)
{
int i;
for(i=0;i<m;i++)
{
for(j=0;j<n;j++)
{
b[i][j]=a[i][j];
}
}
}
Using the output of first function as the input of the second function.
To solve simultaneous equations using matrices, you first need to represent the equations in matrix form. Create a matrix equation by combining the coefficients of the variables and the constants on one side, and the variables on the other side. Then, use matrix operations to manipulate the matrices to solve for the variables. Finally, you can find the values of the variables by performing matrix multiplication and inversion to isolate the variables.
A vector rotation in math is done on a coordinate plane.2D vectors can be rotated using the cross and dot product.3D vectors are rotated using matrix based quaternion math.
No, it does not. You can tell if something is a function or not by using the vertical line test. If there is more than one point at any vertical line, it is not a function.
First of all, if we have any two matrices of sizes mxn and pxq where m, n, p and q are natural numbers, then we must have n=p to be able to multiply the matrices. The result is an mxq matrix. For example, a 3x1 matrix has m=3 and n=1. We can multiply it with any matrix of size 1xq. For example a 2x3 matrix can be multiplied with a 3x1 matrix which has 3 rows and 1 column and the result is a 2x1 matrix. (2x3) multiplies by (3x1) gives a (2x1) matrix. The easy way to remember this is write the dimension of Matrix A and then Matrix B. The two inner numbers must be the same and the two outer numbers are the dimensions of the matrix you have after multiplication. For example Let Matrix A have dimensions (axb) multiply it by matrix B which has dimensions (bxc) = the result is matrix of dimensions ac. Using the trick we would remind ourselves by writing (a,b)x(b,c)=(a,c). This is technically wrong because the numbers are dimensions, but it is just a method to help students remember how to do it. So, a 3x3 matrix can be multiplied by a 3x 1 but not by a 1,3 matrix. How do you do it? Just multiply each entry in the first row of A by each entry in the first column of B and add the products. Do the same for the next row etc. Many (or should I honestly say MOST) people use their fingers and go along row one and then down column one. The add the products of the entries as they do that. Then they do the same for row two and column two etc. It really does help!
C Examples on Matrix OperationsA matrix is a rectangular array of numbers or symbols arranged in rows and columns. The following section contains a list of C programs which perform the operations of Addition, Subtraction and Multiplication on the 2 matrices. The section also deals with evaluating the transpose of a given matrix. The transpose of a matrix is the interchange of rows and columns.The section also has programs on finding the trace of 2 matrices, calculating the sum and difference of two matrices. It also has a C program which is used to perform multiplication of a matrix using recursion.C Program to Calculate the Addition or Subtraction & Trace of 2 MatricesC Program to Find the Transpose of a given MatrixC Program to Compute the Product of Two MatricesC Program to Calculate the Sum & Difference of the MatricesC Program to Perform Matrix Multiplication using Recursion
#include<
A fast-transpose is a computer algorithm that quickly transposes a sparse matrix using a relatively small amount of memory. Using arrays normally to record a sparse matrix uses up a lot of memory since many of the matrix's values are zero. In addition, using the normal transpose algorithm to transpose this matrix will take O(cols*elements) amount of time. The fast-transpose algorithm only uses a little memory to record the matrix and takes only O(cols+elements) amount of time, which is efficient considering the number of elements equals cols*rows.
It depends on the computer language you're using.
the transpose of null space of A is equal to orthogonal complement of A
Columns and rows can be swapped by transposing them. You can copy a row of cells and using Paste Special and the Transpose option the data can be put into columns. You can do the same with data in columns and transpose them into rows. There is also a Transpose function in Excel.
There is no labeled key for transposing due to a supposed manufacturing error on this model. But if you hold the Function key you can toggle the transpose by using the lowest F and F# keys
Transposing changes the orientation of the cells. You can change values in columns into rows or rows into columns. So if you have values in cells A1, A2 and A3, you could transpose them so they are in B1, C1 and D1. You can transpose by copying and then using the Transpose option in the Paste Special options. You can also use the Transpose function.
You can use the TRANSPOSE function, entering it as an Array function. So if you have something in A2 and A3, you could select C2 and D2 and type the following function: =TRANSPOSE(A2:A3) Instead of pressing Enter, press Ctrl-Shift-Enter and it will enter the formula into the two cells, C2 and D2, and transpose the values. You can apply the same principle to larger ranges. There are also other ways of doing it, like using the INDIRECT function to reference a cell and get its value.
Poor boy
using function we can call the function in the program any where. by using functions we can reduce the code redundancy
means whether the matrix is same or not program for symmetric matrix : include<stdio.h> #include<conio.h> main() { int a[10][10],at[10][10],k,i,j,m,n; clrscr(); printf("enter the order of matrix"); scanf("%d %d",&m,&n); printf("enter the matrix"); for(i=0;i<m;i++) { for(j=0;j<n;j++) scanf("%d",&a[i][j]); } for(i=0;i<m;i++) { for(j=0;j<n;j++) at[i][j]=a[j][i]; } for(i=0;i<m;i++) { for(j=0;j<n;j++) { if(at[i][j]!=a[i][j]) k=1; } } if(k==1) printf("not symmetric"); else printf("symmetric"); getch(); }