Radical 147 simplified is 7 radical 3. radical147= radical 49* radical 3 the square root of 49 is 7 therefore the answer is 7 radical 3
n^3 (n cubed)
5 root 3
One step you usually want to take is to move any perfect square out of the radical. Example 1, with numbers: root(12) = root(4x3) = root(4) x root(3) = 2 root(3) Example 2, with variables: root(y cubed) = root(y squared times y) = root(y squared) times root(y) = y root(y)
x^3-x = x(x^2-1) = x(x+1)(x-1)
Radical 147 simplified is 7 radical 3. radical147= radical 49* radical 3 the square root of 49 is 7 therefore the answer is 7 radical 3
Answer: 12
12x^2√5x
n^3 (n cubed)
sqrt(27) = 3*sqrt(3).
5 root 3
√108 = √(36 x 3) = √36 x √3 = 6√3
I think you want: √300 = √(100 x 3) = √100 x √3 = 10√3
Start by finding a common denominator. If the radical includes the entire fraction (3/4 for the first part), the common denominator would be square root of 12.
Let's assume that \/" is the radical sign.3\/"16The first thing to do would be to solve for the part under the radical.\/"16 = 4Then substitute that into the original problem.3\/"163*412 is the final answer.
8√12/5√4 = 8√(3*4)/5√4 = 8(√3)/5 = 8/5*√3
To simplify x3-9x, you factor out the x, leaving you with x(x2-9). You can then take the square root of both numbers and end up with x(x+3)(x-3).