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5x - y = 5

5x - 3y = 15

from the first equation:

5x = 5 + y , substitute it in the second equation:

5 + y - 3y = 15

5 -2y = 15

-2y = 15 - 5

-2y = 10

y = -5

Now,solve for x :

5x = 5 +y

5x = 5 -5 = zero

x = zero

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Q: Solve the system using substitution 5x-y equals 5 diveded by5x-3y equals 15?
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