square root of (2 ) square root of (3 ) square root of (5 ) square root of (6 ) square root of (7 ) square root of (8 ) square root of (9 ) square root of (10 ) " e " " pi "
square root 2 times square root 3 times square root 8
the square root of 3, the square root of 5, the square root of 6, the square root of 7, the square root of 8 etc
Square root (75) / square root (3) = 5
It is the square root of 8
sqrt(360) - sqrt(250)/sqrt(5) = 11.90, approx.
No. It's square root is 18.97 rounded.
The square root of 36.0 is 6.0. To find the square root of a number, you are looking for the number that, when multiplied by itself, equals the original number. 36.0 can be written as 6.0 * 6.0. So the square root of 36.0 is 6.0.
It is 6 times the square root of 10
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No because it can't be expressed as a fraction
Each side of the square will be the square root of 360 in feet which is about 18.974 rounded up to 3 decimal places
Multiply the thirty and the twelve together to get three hundred and sixty. Now you have the square root of three hundred and sixty. Then take out any square roots you know. In 360, the obvious choice is 36. Take the square root of 36, six, out of the square root. When you take thirty-six out, you are left with the square root of ten. You now have six square root of ten.
Out of these numbers, 225 is a square number since the square root of 225 is 15.
Try it! Find the square of some integers, until you either (a) find one that gives exactly 360 when squared, or (b) find two consecutive integers, one of which is smaller, the other larger, than 360. You can also take your calculator and find the square root of 360. If it is an integer (no decimals), that means it is a square number.
The square root of the square root of 2
Let the coefficient by 'x' Hence its square root is x^(1/2) or x^(0.5) Then the square root again is [x^(1/2)]^(1/2) Third time over {[x^(1/2)]^(1/2)}^(1/2) Now the rules of indices are [x^(n)[^(m) = x^(nm) When terms are 'nested' , multiply together. Also x^(n) X x^(m) = x^(n+m) x^)n) / x^(m) = x^(n-m) However, the first rule (nesting) applies in this case, when you multiply the indices together/ Hence x^(1/2 X 1/2 X 1/2) = x^(1/8) , Which is the 8th root.!!!!!