16+18+20= 54
Let x be the smallest of the consecutive odd integers. Since consecutive odd integers differ by 2, we havex + (x + 2) + (x + 4) + (x + 6) = -2204x + 12 = -220 (subtract 12 to both sides)4x = -232 (divide by 4 to both sides)x = -58Thus, the four consecutive odd integers whose sum is -220 are -58, -56, -54, and -52.
The numbers are 55, 56 and 57 OR 54, 56 and 58
The numbers are: 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 +02 = 2 +03 = 5+04 = 9+05 = 14+06 = 20+07 = 27+08 = 35+09 = 44+10 = 54+11 = 65 or 32 and 33
53 and 55
The integers are -19, -18 and -17.
52 + 54
17, 18, and 19
16+18+20= 54
The first integer is 17.
The numbers are 52, 53 and 54.
17+18+19
53+54 = 107. Far too easy.
57
There is no set of four consecutive odd integers for 204. The only set is even: 48, 50, 52 and 54.
Let x be the smallest of the consecutive odd integers. Since consecutive odd integers differ by 2, we havex + (x + 2) + (x + 4) + (x + 6) = -2204x + 12 = -220 (subtract 12 to both sides)4x = -232 (divide by 4 to both sides)x = -58Thus, the four consecutive odd integers whose sum is -220 are -58, -56, -54, and -52.
16 18 20