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The brakes of a car are applied when it is moving at 100km per hour and provide a constant deceleration of 10 meters per second per second. how far does the car travel before coming to a stop?
Wiki User
∙ 14y ago
Let us first analyse the question. The car is travelling at some speed. And it has to stop. What distance will it cover before it stops?
Firstly, it is travelling at a speed of 100 kilometers per hour. And the deceleration provided is given in meters per second. So, let us convert all the data into same terms.
that is, 100 kmph = 100*1000 meters per hour
So, it is travelling 100,000 metres in one hour. And one hour has 3600 secs.
Hence the car is travelling 100000/3600 meters in ONE second
that is 27.77778 or approx = 27.8 meters/second.
Or simply, 100 km/hr = (100*5/18) mts/sec = 27.8 mts/sec
Now, we have a formula to calculate the distance covered, acceleration and deceleration provided and the initial and final speeds.
v2-u2 = 2*a*s ,a is acceleration/deceleration, s is distance, v is final speed, u is initial speed.In this case, final speed is zero and deceleration = negative acceleration
02-(27.8)2 = 2*(-10)*s
-20*s = - (27.8*27.8)
s = 38.642 meters
Hence the car travels a distance of 38.642 metres before it comes to a stop.
Wiki User
∙ 14y ago
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