The length of the sides of the rhombus are 10cm, as a rhombus has equal sides.
since the diagonals of a rhombus are perpendicular,
ratio of
side of rhombus to
1/2 a diagonal to
1/2 of another diagonal
is 5:4:3 (pythagorean thriple),
hence ratio of side of rhombus to
1 diagonal
to another diagonal
is 5:8:6.
since 5 units = 10cm
8 units = 16cm
6 units = 12cm
and there are your diagonals.
The ratios of areas are the squares of the ratio of lengths (and the ratio of volumes are cubes of the ratio of lengths). As the perimeter of the second is twice the perimeter of the first, each length of the second is twice the length of the first, and so the ratio of the lengths is 1:2 Thus the ratio of the areas is 1²:2² = 1:4. Therefore the surface area of the larger prism is four times that of the smaller prism.
The ratio is [ 4/x per unit ].
The perimeter of the larger polygon will have the same ratio to the perimeter of the smaller as the ratio of the corresponding sides. Therefore, the larger polygon will have a perimeter of 30(15/12) = 37.5, or 38 to the justified number of significant digits stated.
8 27
10Scale factors are based on linear measures. The ratio of areas is the square of the rations of lengths. The ratio of the areas is 900/9 = 100, so the ratio of lengths is the square root of100 = 10.
The lengths of the diagonals work out as 12 cm and 16 cm
They are the same length, so 1:1 * * * * * In fact that is the one ratio they cannot be. A rhombus with equal diagonals is a square. The ratio of the lengths can have any other positive value.
No, they do not have that property. The quadrilaterals that have that property are the rhombus (and subsequently, the square) and the kite. The only property I'm aware of diagonals of a trapezoid having is the fact that they cut each other in the same ratio, which happens to be the ratio between the lengths of the parallel sides.
The ratio of the perimeters of two similar shapes is the same as the ratio of their corresponding side lengths. Since the ratio of the side lengths of the two rectangular tables is 4:5, the ratio of their perimeters will also be 4:5. Therefore, the ratio of the perimeter of the first table to the perimeter of the second table is 4:5.
It is the same.
To find the area ratio of two similar polygons, you square the ratio of their corresponding side lengths. If the ratio of the sides is ( r ), the area ratio will be ( r^2 ). The perimeter ratio of two similar polygons is simply the same as the ratio of their corresponding side lengths, ( r ). Thus, if the side length ratio is known, both the area and perimeter ratios can be easily calculated.
The ratios of areas are the squares of the ratio of lengths (and the ratio of volumes are cubes of the ratio of lengths). As the perimeter of the second is twice the perimeter of the first, each length of the second is twice the length of the first, and so the ratio of the lengths is 1:2 Thus the ratio of the areas is 1²:2² = 1:4. Therefore the surface area of the larger prism is four times that of the smaller prism.
You need to find the perimeter of one by adding together the lengths of all its sides. The perimeter of the similar shape is the answer multiplied by the similarity ratio.
In a kite, the diagonals intersect at right angles, and one of the diagonals bisects the other. The ratio of the lengths of the diagonals can vary depending on the specific dimensions of the kite, but generally, the longer diagonal (which connects the vertices of the unequal angles) is greater than the shorter diagonal (which connects the vertices of the equal angles). There isn't a fixed ratio applicable to all kites, as it depends on their specific dimensions.
Given that the perimeter of the triangle is 90 centimeters, we can determine the actual side lengths by multiplying the ratio by a common factor. The total ratio value is 5 + 12 + 13 = 30. To find the actual side lengths, we divide the perimeter by this total ratio value: 90 / 30 = 3. Therefore, the side lengths of the triangle are 5 x 3 = 15 cm, 12 x 3 = 36 cm, and 13 x 3 = 39 cm.
get the lengths of all sides of shape for example : 12 : 10 : 14 now by simplifying . . . 6 : 5 : 7
To find the perimeter of polygon abcd, we need to know the lengths of its sides or the ratio of similarity between the two polygons. Since polygons abcd and efgh are similar, their perimeters are proportional to the corresponding sides. If you provide the perimeter of efgh and the ratio of similarity, I can help you calculate the perimeter of abcd.