The length of the sides of the rhombus are 10cm, as a rhombus has equal sides.
since the diagonals of a rhombus are perpendicular,
ratio of
side of rhombus to
1/2 a diagonal to
1/2 of another diagonal
is 5:4:3 (pythagorean thriple),
hence ratio of side of rhombus to
1 diagonal
to another diagonal
is 5:8:6.
since 5 units = 10cm
8 units = 16cm
6 units = 12cm
and there are your diagonals.
The ratios of areas are the squares of the ratio of lengths (and the ratio of volumes are cubes of the ratio of lengths). As the perimeter of the second is twice the perimeter of the first, each length of the second is twice the length of the first, and so the ratio of the lengths is 1:2 Thus the ratio of the areas is 1²:2² = 1:4. Therefore the surface area of the larger prism is four times that of the smaller prism.
The ratio is [ 4/x per unit ].
8 27
The perimeter of the larger polygon will have the same ratio to the perimeter of the smaller as the ratio of the corresponding sides. Therefore, the larger polygon will have a perimeter of 30(15/12) = 37.5, or 38 to the justified number of significant digits stated.
16:1
The lengths of the diagonals work out as 12 cm and 16 cm
They are the same length, so 1:1 * * * * * In fact that is the one ratio they cannot be. A rhombus with equal diagonals is a square. The ratio of the lengths can have any other positive value.
No, they do not have that property. The quadrilaterals that have that property are the rhombus (and subsequently, the square) and the kite. The only property I'm aware of diagonals of a trapezoid having is the fact that they cut each other in the same ratio, which happens to be the ratio between the lengths of the parallel sides.
It is the same.
The ratios of areas are the squares of the ratio of lengths (and the ratio of volumes are cubes of the ratio of lengths). As the perimeter of the second is twice the perimeter of the first, each length of the second is twice the length of the first, and so the ratio of the lengths is 1:2 Thus the ratio of the areas is 1²:2² = 1:4. Therefore the surface area of the larger prism is four times that of the smaller prism.
You need to find the perimeter of one by adding together the lengths of all its sides. The perimeter of the similar shape is the answer multiplied by the similarity ratio.
get the lengths of all sides of shape for example : 12 : 10 : 14 now by simplifying . . . 6 : 5 : 7
L + W = P/2 = 18. In ratio of 7:2 sides are 7/9 x 18 and 2/9 x 18 ie 14 and 4
the ratio of the perimeter of triangle ABC to the perimeter of triangle JKL is 2:1. what is the perimeter of triangle JKL?
These are not similar rectangles so there is no obvious candidate for the ratio. Is it ratio of lengths (sides, perimeter, diameter), or ratio of area?
The sides are 24 metres and 36 metres.
Let the lengths be 2x and 5x If: 2*(2x+5x) = 224 then x = 16 So therefore the lengths are 32 and 80 because 32+80+32+80 = 224