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The way this is written is a little vague, so I will solve it both ways.

First: (5-y)>3
Set as equality and solve for the boundary
5-y=3
y=2
Find whether 0 is a solution. (Using 0 is the easiest, since all products vanish)
5-0>3 Yes.
The side of the boundary including 0 is the solution.
{y: y<2} ◄

Second, the problem could be translated as |5-y|>3 "All differences of 5 and y"
This would include all values of -(5-y)>3 as well. This can be written as y-5>3
Set as equality and solve for the boundary
y-5=3
y=8
Find 0
0-5>3 No.
The side of the boundary not including 0, added to the earlier answer is the solution here.
{y: y<2 U y>8} ◄

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Q: The difference of 5 and y is greater than 3?
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