The way this is written is a little vague, so I will solve it both ways.
First: (5-y)>3
Set as equality and solve for the boundary
5-y=3
y=2
Find whether 0 is a solution. (Using 0 is the easiest, since all products vanish)
5-0>3 Yes.
The side of the boundary including 0 is the solution.
{y: y<2} ◄
Second, the problem could be translated as |5-y|>3 "All differences of 5 and y"
This would include all values of -(5-y)>3 as well. This can be written as y-5>3
Set as equality and solve for the boundary
y-5=3
y=8
Find 0
0-5>3 No.
The side of the boundary not including 0, added to the earlier answer is the solution here.
{y: y<2 U y>8} ◄
No because 5/12 is greater than 3/8
3/6 can be simplified to 1/2, and 1/2 is greater than 2/5. So, 3/6 is greater then 2/5.
For example, we know that 7 is greater than 3. So, the symbol is: 7>3. We know that 2 is less than 5. So the symbol would be: 2<5.
Yes because A > B, B > C, so A has to be > C.ExampleA=5B=3C=1A (5) > B (3)B (3) > C (1)A (5) > C (1)
the sum of two whole numbers is always greater than either addend* * * * *No.Consider:5 is a whole number-3 is a whole number.Their sum is 2, which is notgreater than one of the addends (5).
If you mean greater than then -5 is not greater than 3 because -5 is less than 3
5 8 is greater than 3 8.
Is 2/3 greater than -5
6/5 is greater than 3/3 by 1/5
-3
No, 3/5=0.6, a number less than one cannot be greater than a number greater than one.
Negative 3 is greater than negative 5
You're asking for the difference: (3x + 2) - (5 - 7x).(3x + 2) - (5 - 7x) =3x + 2 - 5 + 7x =10x - 3.It is (10x - 3) greater.
Less than 5: 1,2,3,4 Greater than 3: 4,5,6,7
greater than
5/7 is greater than 3/7
No because 5/12 is greater than 3/8