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The length of a new rectangle playing field is 8 yards longer than quadruple the width If the perimeter of the rectangle playing field is 496 yards What are its dimensions?
Wiki User
∙ 14y ago
The length is 200 yards and the width is 48 yards.
length + width = 248 yards, and length = (4 x width) + 8 yards.
substituting (4 x width) + 8 yards for length,
(4 x width) + 8 yards + width = 248 yards;
simplifying, width = 240/5 yards = 48 yards;
then length = 248 - 48 yards = 200 yards
Wiki User
∙ 14y ago
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The perimeter of a rectangular playing field is 244 feet If its length is 2 feet longer than twice its width what are the dimensions of the field?
The answer is W=40 and L=82 If you're wondering how to solve it, then let "P" represent perimeter "L" represent length and "W" represent width. P=2L+2W L=2W+2 244=2(2W+2)+2W 244=4W+4+2W 244=6W+4 6W=244 244/6W= W=40 Now plug the 40 in for w in: L=2W+2 L=2(40)+2 L=80+2 L=82 final answer: L=82 and W=40
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