Let the width be x, so the length is 2x - 4. Since one half of the perimeter is 26 feet ( 52/2), then we have:
x + (2x - 4) = 26
3x - 4 = 26
3x - 4 + 4 = 26 + 4
3x = 30
3x/3 = 30/3
x = 10
2x - 4 = 2(10) - 4 = 20 - 4 = 16
Thus the width of the rectangular garden is 10 feet, and the length is 16 feet.
To solve this problem using algebraic equations :Set the variable x as the width of the gardenThe length of the garden becomes 2x + 4 (4 feet more than twice X).The perimeter is equal to twice the length plus twice the width P = 2L + 2Wand has the value 98 feet.Substituting the terms for length and width,98 = 2 L + 2 W so 2(2x+4) + 2(x) = 982(2x+4) + 2 (x) = 984x + 8 + 2x = 986x = 90x = 15 and 2x+4 = 34The width is 15 feet, the length is 34 feet.Verifying, you have 15+15+34+34 = 98
To solve this problem using algebraic equations :Set the variable x as the width of the gardenThe length of the garden becomes 2x - 4 (4 feet less than twice X).The perimeter is equal to twice the length plus twice the width P = 2L + 2Wand has the value 52 feet.Substituting the terms for length and width,52 = 2 L + 2 W so 2(2x-4) + 2(x) = 522(2x-4) + 2 (X) = 524x - 8 + 2x = 526x = 60x = 10 and 2x-4 = 16The width is 10 feet, the length is 16 feet.Verifying, you have 10+10+16+16 = 52
Let the length be 2x-3 and the width be x:- So: 2*(2x-3+x) = 82 feet => 6x-6 = 82 => x = 14 and 2/3 Therefore the dimensions are: length = 26 ft 4 ins and width = 14 ft 8 ins
Length = (Perimeter - twice width) / 2
Both the side lengths and the perimeter are linear measurements, therefore they are proportional. In other words, twice the side length results in twice the perimeter.
If the perimeter is 84 feet and the length is twice the width, then the length will be 28 feet and the width will be 14 feet.
divide perimeter by 6.
28
14 feet (14+14+28+28 = 84)
Twice the (width plus length)
Width = 16 feet Length = 38 feet
A farmer wants to fence a rectangular garden whose perimeter is 60 yards. The length of the garden exceeds twice the width by 6 yards. What are the length and width of the garden?
Doubling the width of a rectangular rug will affect the perimeter because the total length and width will be doubled. The area will be twice the length times the width.
The standard perimeter of a rectangular building can be found by adding the lengths of all four sides. It is twice the sum of the length and width of the building.
The width is half the length: The perimeter is twice the length plus twice the width. If the perimeter is 3 times the length, twice the width must be the length.
To solve this problem using algebraic equations :Set the variable x as the width of the gardenThe length of the garden becomes 2x + 4 (4 feet more than twice X).The perimeter is equal to twice the length plus twice the width P = 2L + 2Wand has the value 98 feet.Substituting the terms for length and width,98 = 2 L + 2 W so 2(2x+4) + 2(x) = 982(2x+4) + 2 (x) = 984x + 8 + 2x = 986x = 90x = 15 and 2x+4 = 34The width is 15 feet, the length is 34 feet.Verifying, you have 15+15+34+34 = 98
The length works out as 12 cm and the width works out as 5 cm Check: 2*(12+5) = 34 cm which is the perimeter