10+8+6 = 24 inches
The lengths of the sides of the triangle are: 2*sq rt of 10, 5*sq rt of 2 and sq rt of 10 The 3 sides added together equals the perimeter which works out as 3* sq rt of 10 plus 5*sq rt of 2 in surd form
Well if two triangles have sides of the same length, then by SSS they are congruent. In addition, if they have sides of the same length, their perimeters would be the same. So at first it seems like the answer would be yes. However, if is easy to come up with two triangles with the same perimeter whose sides do not have the same length Triangle 1 has sides 10, 15 and 30 to know if this is a triangle, we need the length of any side to be less the sum of the other two sides. So 10
it is an acute triangle.
Being a polygon, you need to know the number of sides. 'Polygon'; Many sides Trigon (Triangle) ; 3 sides Tetragon (Rectangle) ; 4 sides Pentagon ; 5 sides Hexagon ' 6 sides Heptagon ; 7 sides Octagon ' 8 sides Nonagon ' 9 sides Decagon ; 10 sides You need to know and select the number of sides.
Perimeter of triangle: 6+8+10 = 24 inches
26.8
perimeter = sum of sides = 6 in + 8 in + 10 in = 24 in
For the perimeter, add up all of the sides: 6+8+10= 24
Perimeter = 6 + 8 + 10 = 24 inches
add the sides 6+8+10= 24 :)
Perimeter of a triangle is given by: sum of the three sides =(10+15+18)cm =43cm Done.
6+8+10=24
10+8+6 = 24 inches
To find the perimeter you just add up the sides. So it would be 24 inches.
42cm
6+8+10=24The perimeter of the triangle is 24 inchesThe perimeter is all the side lengths added up, so that triangle would have a perimeter of 24 inches.6+8+10=24 inches