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Best Answer

'42' being an even number will divide by '2'

Hence

2)42 = 21

3)21 = 7

7 ) 7 = 1

So the prime factors of '42' are 2^(1) X 3^(1) x 7^(1).

#NB the '1' is the exponent. 2,3, & 7 are the primes.

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lenpollock

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7mo ago
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8y ago

No exponents are needed because: 2 times 3 times 7 = 42

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Q: The prime factorization of 42 using exponents?
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What is the least common multiple of 28 and 42 found using prime factorization?

First you need to find the prime factors of 28 and 42. 28= 7x22 42= 7x3x2 Then you multiply 7x3x22, the product of which is 84, which is your answer.


Prime factorization for 84?

The prime factor decomposition of 84 is: 2 x 2 x 3 x 7 If you want to see my working (in case I made a mistake): 84/2=42 (42 is not prime), 42/2=21 (21 is not prime), 21/3=7 (7 is prime, so stop here) factors: 2,2,3 and 7


What are the factors and prime factors of 126?

126 is a composite number; it has factors other than 1 and itself.The 12 factors of 126 are 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, and 126.The factor pairs of 126 are 1 x 126, 2 x 63, 3 x 42, 6 x 21, 7 x 18, and 9 x 14.The proper factors of 126 are 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, and 63 or,if the definition you are using excludes 1, they are 2, 3, 6, 7, 9, 14, 18, 21, 42, and 63.The prime factors of 126 are 2, 3, 3, and 7. Note: There is repetition of these factors, so if the prime factors are being listed instead of the prime factorization, usually only the distinct prime factors are listed.The distinct prime factors of 126 are 2, 3, and 7.The prime factorization of 126 is 2 x 3 x 3 x 7 or, in exponential form, 2 x 32 x 7.-ProMode- Thank you :)1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, 126The factors of 126 are 1, 2, 3, 6, 7, 9, 14, 18, 21, 42, 63, and 126.


What is the prime factorization of a negative 42 and how do you solve it?

The concept of prime factorisation is normally applied to positive integers only. This is because once you consider negative numbers, the results become ambiguous. One of the most important theorems of factorisation is that the prime factorisation of any integer is unique. That does not apply to negative integers. As long as an odd number of factors is negative, the overall product is negative so, -42 = -2*3*7 or 2*(-3)*7 or 2*3*(-7) : hardly unique!


How do you get 29 using only using 1 2 3 4 once?

We can get 29 by using their squares like: (42 + 32 + 22) / 1 = 29