If the lawn is twice as long as it is wide, and length times width is 288, then 3x = 288, or x = 96. The lawn is then 96 by 192 feet. This means that the perimeter is 576 feet (96 + 96 + 192 + 192).
Let the length be 2x and the width be x: 2(2x+x) = 66 the perimeter in feet 4x+2x = 66 6x = 66 x = 11 Therfore: length = 22 feet, width = 11 feet and 22*11 = 242 square feet.
Stake out the rectangle with a length of 22-ft and a width of 11-ft.Area = (11 x 22) = 242 square feet.Perimeter = (11 + 22 + 11 + 22) = 66 feet.Please pass the word to Sohan:Although these are the demonations she's looking for, this pen will not hold many sheep.
square the first term, plus twice the product of the first and the secon, then square the second.
square root of 80 simplified= 16*5= 4 squared *5
Diagonal = sqrt (twice the square of a side) eg: square of side 8 units, d = sqrt(2 x 64) = sqrt 128 = 11.3137
4Improved Answer:-30 feet of fencing will be needed
you make a square twice one behind the other and you'll find yourself with a rectangular prism's.
$90If the area of the garden is 50 ft2, then the area is represented by the formula50 = l * wIf the length is twice the width, then l = 2w, and50 = 2w * w ===> 50 = 2w2Solving for w, we getw = 5Now the perimeter of the fencing is 2w + 2(2w) = 6w, and with w = 5P = 6(5) = 30.If the fencing costs $3/ft, then we have$3/ft * 30 ft = $90
It is 240 feet because 240*120 = 28800 square feet
15
Twice the (width plus length)
lenght=15, width= 10
$45
Let the length be 2x and the width be x: 2(2x+x) = 66 the perimeter in feet 4x+2x = 66 6x = 66 x = 11 Therfore: length = 22 feet, width = 11 feet and 22*11 = 242 square feet.
If one side is twice the length of the other and the square footage is 800 I'd say one side is 20 feet and the other is 40.
22 ft x 11 ft
Stake out the rectangle with a length of 22-ft and a width of 11-ft.Area = (11 x 22) = 242 square feet.Perimeter = (11 + 22 + 11 + 22) = 66 feet.Please pass the word to Sohan:Although these are the demonations she's looking for, this pen will not hold many sheep.