Let the first angle be x the second angle be 4x and the third angle be 80+4x+x:
x+4x+80+4x+x = 180
Collect like terms:
10x = 180-80
10x = 100
x = 10
Therefore the measure of the second angle is 40 degrees.
In a triangle the measure of the first angle is four times the measure of the second angle. The measure of the third angle is 18 degrees more than the second angle. What is the measure of the first angle? 68 43 17 95
If two angles are complementary, then they equal 90 degrees. If one angle is 62 degrees we subtract it from 90 and get 38 degrees.
The second angle must be 2 x (90 - 77) ie 26o, so the other is 64o
54 degrees
False. Assume that you had a two right triangles with one congruent acute (<90 degrees) angle in common. Let x represent the number of degrees in this angle in both triangles (which we can do since the angles are congruent). Let y represent the degree of the other angle in the first triangle and let z represent the degree of the other angle in the second triangle. We know that the sum of the degrees of the angles in a triangle is 180. So for the first triangle we have, 90+x+y = 180 For the second triangle, 90+x+z=180 Therefore, 90+x+y=90+x+z Subtract the 90+x from each side: y=z Therefore the degrees of the angles of the two triangles both are 90 [because they are both right triangles], x [because we said that this is the number of degrees of the congruent angles given in the problem], and y [because y=z]. Because the three angles of both triangles have the same measurement, the triangles must be similar.
In a triangle the measure of the first angle is four times the measure of the second angle. The measure of the third angle is 18 degrees more than the second angle. What is the measure of the first angle? 68 43 17 95
The angles are 40, 80 and 60 degrees.
The sum of the measures of the angles of a triangle is 180 degrees. First, calculate the sum of the two known angles. Then subtract that result from 180. That difference is the measure of the third unknown angle. Given: One angle of a triangle is 15 degrees and the second angle of the triangle is 85 degrees. To find: We need to find the third angle of the triangle. Let the third angle of the triangle be x. We know that the sum of the angles in a triangle is 180 degrees. ==> 15 degrees + 85 degrees + x degrees = 180 degrees. ==> 100 degrees + x degrees = 180 degress. ==> x = 180 degrees - 100 degrees. ==> x = 80 degress. Therefore the third angle of the triangle is 80 degrees.
The angles are: 43 degrees. 38 degrees and 99 degrees which all add up to 180 degrees
Let's assume the measure of the first angle is x degrees. The second angle is one-third as large as the first, so its measure is (1/3) * x = x/3 degrees. The third angle is two-thirds as large as the first, so its measure is (2/3) * x = 2x/3 degrees. Therefore, the measures of the angles in the triangle are x degrees, x/3 degrees, and 2x/3 degrees.
If two angles are supplementary, and one angle measures 30 degrees, then the second angle must measure 150 degrees. This is because by definition if two angles are supplementary, then they must up to 180 degrees.
41
100.
If its a right angle triangle then the second acute angle is 62 degrees
If two angles are complementary, then they equal 90 degrees. If one angle is 62 degrees we subtract it from 90 and get 38 degrees.
Angle 1 = 30 degrees Angle 2 = 50 degrees Angle 3 = 100 degrees.
Let the second angle of the triangle be A. Then angle 1 = 2A : and angle 3 = 3A - 12 The internal angles of a triangle total 180° therefore :- 2A + A + (3A - 12) = 180 6A - 12 = 180 : 6A = 192 : A = 32 The angles measure 64° , 32° and 84° .