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Q: The square root of a sum equals the sum of the square roots?
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What is the 4 mistakes of this phrase The sum of the square roots of any two sides of an isosceles triangle is equal to the square root of the remaining side?

The Pythagorean theorem states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides. 1. squares, not square roots 2. right triangle, not isosceles 3. sides opposite the hypotenuse, not any two 4. What are the mistakes, not what is


Is 1 plus the square root of 7 rational or irrational?

The square root of any positive integer can only be a WHOLE NUMBER or IRRATIONAL, so the square root of 7 is irrational.On the other hand, the sum of a rational and an irrational number is always irrational.


Example for sum of a rational number and irrational number?

example for sum of rational numbers is 1/3 + 1/5 Example for sum of irrationals is Pi + e where e is is base of natural log Another is square root of 2 + square root of 3.


What is an unreal number?

Imaginary and complex numbers are an extension of the Real Number system. They are not called unreal. An imaginary number is a non-existent number, like the square root of a negative number. For example, the square root of -4 is 2i (i stands for imaginary). There are also complex numbers, which are defined as the sum of a real number and an imaginary number (e.g. 4 + 3i). An imaginary number does not exist, but can nevertheless be useful in certain applications. An imaginary number is any number that is the product of a real number and the square root of negative one (-1). The square root of -1 is the "unit" of the set of imaginary numbers, and is referred to as "i". As you know, negative numbers cannot have square roots, and so the square root of any negative number is "imaginary". There are also "complex numbers", which are the sum of a real number and an imaginary number. For example 3 + 2i.


What are two numbers whose sum -6 and product is -5?

-2 and -3Check:(-2) + (-3) = -5(-2)(-3) = 6Thus -2 and -3 are not the required numbers. let's find them: x + y = -6xy = -5 y = -x -6x(-x - 6) = -5-x^2 - 6x = -5x^2 + 6x = 5x^2 + 6x + 9 = 5 + 9(x + 3)^2 = 14x + 3 = (+ & -)square root of 14x = -3 (+ & -)square root of 14x = -3 + square root of 14 or x = - 3 - square root of 14y = -x - 6y = 3 - square root of 14 - 6 or y = 3 + square root of 14 - 6y = -3 - square root of 14 or y = -3 + square root of 14Check:(-3 + square root of 14) + (-3 - square root of 14) = -6(-3 + square root of 14)(-3 - square root of 14) = -5 ?(-3)^2 - (square root of 14)^2 = -5 ?9 - 14 = -5Check also tow other numbers.