To find the average of the four 3-digit numbers, we divide the sum by 4, giving us 3615/4 = 903.75. Since the average of the four numbers is 903.75, we can deduce that each number is close to this average. However, since the numbers are 3-digit numbers, they must be close to 900. Therefore, the four numbers are approximately 900, 903, 907, and 905.
The average, in this case, is the sum divided by 4 (since there are 4 numbers).
-2, -1, 0, 1
3,5,7,8
It is 260.
-863
266, 267, 268
Oh, what a happy little math problem we have here! Let's see, we can break down 3615 into four three-digit numbers by dividing it evenly. So, we have 904, 905, 903, and 903. Just like painting a beautiful landscape, sometimes all it takes is a little bit of patience and gentle calculation to find the right combination.
The sum of the first four prime numbers is 17.
The average, in this case, is the sum divided by 4 (since there are 4 numbers).
The sum of the first four prime numbers is 17.
No. The sum of four consecutive integers is two odd numbers plus two even numbers which is an even number. 2001 is an odd number, therefore it cannot be the sum of four consecutive numbers.
The sum is 17.
The sum of the four numbers would be equal to 5 x 4 = 20.
The sum of two odd numbers is always even; the sum of three odd numbers is always odd; the sum of four odd numbers is always even; the sum of five odd numbers is always odd; etc
No, it is impossible.
The sum of the four given numbers is -13.
46,47,48, 28