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Let the numbers be 'n' & 'n+2'

Hence their squares are

n^(2) + (n+2)^(2)

Their sum is

n^(2) + (n+2)^(2) = 130

Multipoly out the second set of brackets

n^(2) + n^(2) + 4n + 4 = 130

Collect like terms

2n^(2) + 4n - 126 = 0

Factor our '2'

n^(2) + 2n - 63 = 0

It is now in quadratic form ; factor

(n + 9)(n - 7) = 0

n = -9

&

n = 7

Are the tweo odd numbers.

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lenpollock

Lvl 16
4d ago

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