Let the numbers be 'n' & 'n+2'
Hence their squares are
n^(2) + (n+2)^(2)
Their sum is
n^(2) + (n+2)^(2) = 130
Multipoly out the second set of brackets
n^(2) + n^(2) + 4n + 4 = 130
Collect like terms
2n^(2) + 4n - 126 = 0
Factor our '2'
n^(2) + 2n - 63 = 0
It is now in quadratic form ; factor
(n + 9)(n - 7) = 0
n = -9
&
n = 7
Are the tweo odd numbers.
3 and 5
Consecutive even numbers are any even numbers which are separated by one (uneven) number... so that 6 and 8 are consecutive even numbers... as are 22, 24 and 26. Similarly, consecutive odd numbers are numbers which are separated by one (even) number... so that 11 and 13 are consecutive odd numbers... as are 31, 33 and 35.
490,000
There are two consecutive odd integers. The numbers are 39 and 41.
112+92 is 202.
If you have two consecutive integers then one of them must be odd and the other must be even. The square of an odd integer must be odd, the square of an even integer must be even. The sum of an odd number and an even number must be odd. Thus, the sum of squares of any two consecutive numbers must be odd. Therefore, the question has no valid answer.
3 and 5
There are no two consecutive odd numbers.
The GCF of consecutive odd numbers is 1.
Consecutive whole numbers will have an odd sum. Consecutive odd numbers, or consecutive prime numbers, will be 29 and 31.
The two consecutive negative odd integers having 74 as the sum of their squares are -5 and -7.
the sum of first 50 consecutive odd numbers is 9801
The sum of the first 30 consecutive odd numbers is 900.
The sum of the first 60 consecutive odd numbers is 3,600.
The sum of the first 900 consecutive odd numbers is 810,000.
The sum of the first 350 consecutive odd numbers is 122,500.
The sum of the first 30 consecutive odd numbers is 900.