144 + 196 = 340 so integers are 12 & 14.
112+92 is 202.
spelling is correct
3 and 5
The only squares of perfect squares in that range are 1, 16, and 81.
144 + 196 = 340 so integers are 12 & 14.
The sum of the squares of two consecutive positive even integers is 340. Find the integers.
112+92 is 202.
12 and 14.
The numbers are 12 and 14.
The two consecutive negative odd integers having 74 as the sum of their squares are -5 and -7.
The sum of the squares of the three consecutive integers 11, 13, 15 = 515
spelling is correct
This is best solved by trial-and-error. If one set of consecutive even integers doesn't work, try a different set. Hint: The integers involved are fairly small.
The sum of the squares of the first 1000 positive odd integers (from 12 to 19992) is 1333333000.
42 + 52 = 16 + 25 = 41
Since 16 + 25=41, we know the integers are 4 and 5.