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The width of a rectangle is 6 inches less than twice the length find the dimension of the rectangle if its area is 108 square inches?
Wiki User
∙ 14y ago
Let the length of the rectangle be L and the width W, then W = 2L - 6
The area of a rectangle = L x W : 108 = L x (2L - 6) = 2L2 - 6L.
Expressing this as a standard quadratic equation gives : 2L2 - 6L - 108 = 0.
This can be factored as (2L + 12)(L - 9) = 0. As we are only concerned with positive solutions then the negative solution can be ignored, thus, When L - 9 = 0 then L = 9.
As L = 9 then W = 2L - 6 = 18 - 6 = 12.
The dimensions of the rectangle are : Width 12 inches, Length 9 inches.
Wiki User
∙ 14y ago
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