Three brothers inherited a cash amount of 120 000 dollars and they divided it among themselves in the ratio of 5-to-2-to-1. How much more is the largest share than the smallest share?

Answer 1

Well, isn't that a happy little math problem! To find the difference between the largest and smallest share, first add up the parts of the ratio: 5 + 2 + 1 = 8 parts total. Then, divide the total cash amount by 8 to find the value of each part. Finally, multiply the value of the smallest share by 5 (the ratio of the largest share) and subtract the value of the smallest share to find the difference. Happy calculating!

Answer 2

To find the shares of the three brothers, we first add the ratio parts (5 + 2 + 1) to get 8 total parts. The largest share would be 5/8 of the total amount, which is $75,000 (5/8 * $120,000). The smallest share would be 1/8 of the total amount, which is $15,000 (1/8 * $120,000). The difference between the largest and smallest share is $75,000 - $15,000 = $60,000.

Answer 3

Well, darling, the largest share would be $75,000 (5 parts out of 8), and the smallest share would be $15,000 (1 part out of 8). So, the difference between the largest and smallest share would be $60,000. Math doesn't lie, honey!

Answer 4

A 5:2:1 ratio means that one party gets x, another get 2x, and the last gets 5x, for a total of 8x. This is also 120,000; so 120 000 = 8x. Dividing by 8, x = 15000. So they get 15 000, 30 000, and 75 000. Thus the largest share was 60 000 (60 thousand) more.