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Let's denote the two numbers as x and y. We know that xy = 80 and x + y = 24. We can solve this system of equations by substituting one equation into the other. By substituting y = 24 - x into the first equation, we get x(24 - x) = 80. Simplifying this equation gives us a quadratic equation: x^2 - 24x + 80 = 0. Solving this quadratic equation will give us the values of x and y.
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What is the maximum product of two numbers if their sum is 48?
the two numbers can only be 24 and24
Two numbers have a sum of 42 and a product of 432 What are the two numbers?
18 and 24 x^2 - 42x + 432 = 0 (x - 18)(x - 24) = 0 x = 18 and x = 24 Why? x + y = 42 xy = 432 y = 432/x x + 432/x = 42 X^2 + 432 = 42x x^2 - 42x + 432 = 0If two numbers have a sum of 42 and a product of 432, the two numbers are 18 and 24.
The sum of two whole numbers is 72 their difference is 48 what are the two numbers?
the sum of two whole numbers are 77 .their difference is 48.what are the two numbers
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xy=24 (x^2)+(y^2)=73
One number is 4 more than 3 times another. Their sum is 24. Find the two numbers.?
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