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Q: Two squares are similar The ratio of a set of sides is 2 and 4 What is the ratio of their areas?
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There are two rectangles what are the ratio of the first to the second?

I guess you mean the ratio of the areas; it depends if the 2 rectangles are "similar figures"; that is their matching sides are in the same ratio. If they are similar then the ratio of their areas is the square of the ratio of the sides.


Two triangle are similar and the ratio of the corresponding sides is 4 3 What is the ratio of their areas?

area of triangle 1 would be 16 and the other triangle is 9 as the ratio of areas of triangles is the square of their similar sides


Two similar polygons have areas of 16 square inches and 64 square inches the ratio of a pair of corresponding sides is 1 to 4 is this true or false?

False: Ratio areas= 16 : 64 = 1 : 4 Ratio of sides = sqrt(ratio of areas) = 1 : 2


What is the area of the larger hexagon of two similar hexagons which have sides in the ratio 3 to 5 and the area of the smaller is 81 sq m?

ratio of areas = (ratio of sides)² ratio of sides = 3 : 5 → ratio of areas = 3³ : 5² = 9 : 25 → area larger = 81 m² ÷ 9 × 25 = 225 m²


Are all squares similar?

Yes, all squares are similar because they are all in proportion. The angles will always be 90 degrees, and the sides proportionate. The same ratio can be created using any two side measures between squares. Thus, all squares are similar.


How the ratio of volume is related to ratio of sides of similar cubes?

The ratio of volumes is directly proportional to the cube of the ratio of their sides. And, incidentally, all cubes are similar.


What are two different size squares that the ratio of their perimeters is the same as the ratio of their areas?

Assume square A with side a; square B with side b. Perimeter of A is 4a; area of A is a2. Perimeter of B is 4b; area of B is b2. Given the ratio of the perimeters equals the ratio of the areas, then 4a/4b = a2/b2; a/b = a2/b2 By cross-multiplication we get: ab2 = a2b Dividing both sides by ab we get: b = a This tells us that squares whose ratio of their perimeters equals the ratio of their areas have equal-length sides. (Side a of Square A = side b of Square B.) This appears to show, if not prove, that there are not two different-size squares meeting the condition.


What is the ratio of corresponding sides of two similar triangles whose areas are 36 square inches and 144 square inches?

Areas are proportional to the square of corresponding sides. Therefore, in this case: * Divide 144 by 36. * Take the square root of the result. That will give you the ratio of the corresponding sides.


What are two solids whose corresponding sides have a constant ratio?

The corresponding sides of similar solids have a constant ratio.


How are similar and congruent figures the same?

Congruent figures are similar - in sides as well as angles. Corresonding angles of similar figures congruent but their sides are not. The sides are all in some fixed ratio. [If that ratio is 1, the figures are congruent.]


If the measure of two corresponding sides of two similar prisms is 4 meters and 5 meters what is the ratio of the surface areas of the prisms?

16/25


Are 2 rectangles similar?

Only if they both have the same ratio of length to width. Since every square has the same ratio of length to width ( it's 1 ), all squares are similar. Gee, when you think about it, every regular polygon is similar to every other regular polygon with the same number of sides. I never realized that.