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Use the Gauss-Jordan method to solve the equation 3x-5y-2z -9 -4x plus 3y plus z 11 8x-5y plus 4z 6?
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∙ 8y ago
Without an equality sign the given terms can't be considered to be an equation.
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∙ 8y ago
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How do you solve each system by the addition method?
solve system equation using addition method 3x-y=9 2x+y=6
How can you use the 'completing the square' method to solve an equation when the coefficient of x squared is more than 1?
i want to solve few questions of completing square method can u give me some questions on it
Test algebra structure and method book 1 answers?
What does it mean when it says to solve if tr equation or has no solution state that fact
How do you solve systems by using the substitution method?
You solve one of the equation for one of the variables. For example, if the variables involved are "x" and "y", you might solve for "y". It doesn't really matter what variable you solve for first, so you can solve for whatever variable is easiest to solve. Then - assuming you got, for example, "y = 3x -1", in this example you would replace every "y" by "3x - 1" in the other equation or equations.
Solve the equation X2 X1980?
it is not an equation (there no equality in it!)
How do you solve a linear equation using the symbolic method?
you cant
How can you solve a linear equation?
by elimination,substitution or through the matrix method.
How do you solve each system by the addition method?
solve system equation using addition method 3x-y=9 2x+y=6
How do you find the locus of all points that lie on the graphs of both x plus 2y equals 1 and 2x -y equals 12?
You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".You solve the two equations simultaneously. There are several ways to do it; one method is to solve the first equation for "x", then replace that in the second equation. This will give you a value for "y". After solving for "y", replace that in any of the two original equations, and solve the remaining equation for "x".
Solve the equation by substitution method x-y equals 5?
x+y=5
Can you say that an iterative methods to solve a non-linear equation is actually a numerical method?
Yes, you can. Any iterative method/algorithm that is used to solve a continuous mathematics problem can also be called a numerical method/algorithm.
How can you use the 'completing the square' method to solve an equation when the coefficient of x squared is more than 1?
i want to solve few questions of completing square method can u give me some questions on it
Why quadratic equation is used?
It's quite convenient, for it offers a general method to solve any equation that involves a polynomial of degree two (in one variable).
Solve py plus qz equals pq by charpit method in partial differential equation?
z=pq
Use the guess-and-check method to solve the equation?
OK for very simple equations but not much good otherwise.
Can you solve a quadratic equation without factoring?
using the quadratic formula or the graphics calculator. Yes, you can do it another way, by using a new method, called Diagonal Sum Method, that can quickly and directly give the 2 roots, without having to factor the equation. This method is fast, convenient and is applicable to any quadratic equation in standard form ax^2 +bx + c = 0, whenever it can be factored. It requires fewer permutations than the factoring method does, especially when the constants a, b, and c are large numbers. If this method fails to get answer, then consequently, the quadratic formula must be used to solve the given equation. It is a trial-and-error method, same as the factoring method, that usually takes fewer than 3 trials to solve any quadratic equation. See book titled:" New methods for solving quadratic equations and inequalities" (Trafford Publishing 2009)
Can you solve for a variable in an equation?
Sure. You can always 'solve for' a variable, and if it happens to be the only variable in the equation, than that's how you solve the equation.
