Let's denote the two numbers as x and y. We know that xy = 60 and x + y = 66. By solving these two equations simultaneously, we can find that the two numbers are 6 and 10. This is because 6 * 10 = 60 and 6 + 10 = 16, which satisfies both conditions.
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Set up Quadratix Eq'n
x^(2( + 66x + 60 = 0
Complete the
Square
x^(2) + 66x = -60
(x - 33)^(2) - )33)^(2) = -60
(x - 33)^(2) = -60 + 33^(2)
(x - 33)^(2) = -60 + 1089
( x - 33)^*2) = 1029
Square root both sides
x - 33 = sqrt(1029( = +/- 32.078....
x = -33 +/- 32.078.....
x = -0.92197.... & -65.078.... are the two numbers.
The numbers are: 33 -7 times sq rt of 21 and 33 +7 times sq rt of 21
83
Assume we want to determine the integers that multiply to obtain -24.Here are the possible pairs:-1 and 241 and 242 and -12-2 and 123 and -8-3 and 84 and -66 and -4
21,22,23 21,22,23
The numbers are 65 and 66.
Whatever grade you get for 66%