There are infinitely many possible answers.
A couple of examples:
1*2*55
2*2.75*20
5 and -3
-29
3 and -5.
3 x 61
There are no two real numbers that will add to -9 and multiply to 81. Using complex numbers, the two numbers are: (-9/2 + i9/2√3) and (-9/2 - i9/2√3)
They are: 2*5*11 = 110
135
The numbers are: -5 and 3
111 = 3*37
For any number x, you can multiply any of it's factors by x/factor to get x. For 110, 11 is a factor, and 110/11 is 10. So 10 * 11 = 110. In the case of 110, all of the factors are as follows: 1, 2, 5, 22, 55, 110 There is a pattern here; the first and last numbers multiplied together will give you the value 110, and then the 2nd numbers from the front and back will multiply to get 110, and so on. This is true for all integers. If you find the prime factorization of the number, you can determine all the possible combinations of multiplying numbers to get the original number, that is to say, where you can multiply 3, 4 or more numbers together to get the original number. For example, the prime factorization of 110 is as follows: 2, 5, 11. So you can see that 2*5*11=110 as well.
1, 3, 13, 39.
3675
135
513
The three prime numbers which multiply to make 231 are 3 x 7 x 11.
-5 and +3
There are 4 of them which are 2*3*3*3 = 54