28+28=56
24+36=56
36 + 20
X = 135 and y = 15 Solved by addition and substitution
56
If: x+y = 8 and 2x-y = 5 Then by adding the equations together: 3x = 13 or x = 13/3 By substitution into the original equations: x = 13/3 and y = 11/3
Not until it equals something. Equations have equals signs.
The equations are identical in value, ie the second is merely twice the first...
28+28=56
You need two equations to use the addition method.
the answer
When talking about a "system of equations", you would normally expect to have two or more equations. It is quite common to have as many equations as you have variables, so in this case you should have two equations.
X = 135 and y = 15 Solved by addition and substitution
Addition and subtraction are mathematical processes. They can be used in equations, which are statements that the values of two mathematical expressions are equal, but they are not equations by themselves.
93-56 equals = 37
62-56 equals = 6
56-43.789 equals = 12.210999999999999
They can but don't have to.
56 plus zero
56