Factors of 20 are 1, 2, 4, 5, 10 and 20. And their sum is 1 + 2 + 4 + 5 + 10 + 20 = 32.
There is no such combination to form an even no. 20 by combing 5 odd nos. as odd+odd=even even +even=evenodd+even=odd even+odd=odd adding 5 odd like
(1,20),2,10,4,5
because you have a number times itself 6x6.
No. Here's why: you have a² + b² = c². If a is odd, then a² will also be odd (and if a is even, then a² will also be even. Same goes true for b² and c².If a² & b² are both odd, then you have odd + odd, which is even. Why is {odd + odd} always even, you may ask. An informal proof could be something like this:Let m & n be non-zero integers.So 2m and 2n are guaranteed to be even,then (2m + 1) & (2n + 1) are both odd.Add them together: (2m + 1) + (2n + 1) = 2m + 2n + 2 = 2(m + n + 1) which is even.And why is a² odd, when a is odd: if a is odd, then it does not have 2 as one of its factors. Since you square the number, you have not added any additional factors, so it still does not have 2 as a factor. If a was even, then it will have 2 as a factor, when you square it, you now have 2 as well as 2² as a factor, so the square is even as well.
NO because 5 is a factor of 20 and its odd
The factors of 20 are 1,2,4,5,10 and 20. Two are odd, four are even.
Yes, the factors of all odd numbers are odd numbers.
Because 55 is an odd number. All the factors of odd numbers are odd.
48 has both even and odd factors.
All odd numbers have odd factors.
All nonzero numbers have factors. Some factors are even numbers, some factors are odd numbers.
Any odd number.
3,7,11,13
All of the odd numbers in that range can be factors.
All nonzero numbers have factors. Some factors are odd numbers. 3 is an odd factor of 12.
The odd factors of 70 are: 1, 5, 7, and 35. The sum of these factors is 48.