28 = 256
4x4x4x4 = 4^(4) = 256 NB 4x4x4x4 = 16 x 4x 4 = 64 x 4 = 256
(-4)^(4) = (+)256 -4x-4x-4x-4 = (+)16X (+)16 = 256
You multiply the exponents.
when two numbers are multiplied together that are exponents you multiply the bases amd add the exponents the relationship would simply be that the product exponents are the sum of the exponents being multiplied in the question
You add exponents when multiplying. Ex: (xm) × (xn) = xm+n
28 = 256
256 = 28.
In exponents, (4^4) represents 4 raised to the power of 4. This means multiplying 4 by itself four times: (4 \times 4 \times 4 \times 4). The result is (256), since (4^4 = 256).
The prime factorization with exponents for 250 is: 2 x 53
4x4x4x4 = 4^(4) = 256 NB 4x4x4x4 = 16 x 4x 4 = 64 x 4 = 256
The exponents are added.
65,536 = 256 x 256 = 256²
256
you do not do anything when you add numbers with exponents. you just figure out the answer. it is only if you multiply numbers with exponents, where you add the exponents..
nth root (a) = a^(1/n) mth root a^(1/m) a^(1/n) + a^(1/m) = a^(1/n) + a^(1/m) However. when multiplying a^(1/n) X a^(1/m) = a^([m + n]/[mn]) Think of addition of fractions , where the exponents are concerned. NB This can only be done when the coefficient 'a' is the same for both numbers. NNB a^(1/n) means the 'n th root' of 'a'.
(247, 256, 256, 265) The mean is 256 The mode is 256 The median is 256
To simplify the expression ((4^5 \times 4^{-3})^{-2}), first combine the exponents: (4^{5 - 3} = 4^2). Then, raising it to the power of (-2) gives (4^{2 \times -2} = 4^{-4}), which is equal to (\frac{1}{4^4} = \frac{1}{256}). Therefore, the expression is equal to (\frac{1}{256}), confirming that it is equal to 1 over 256.