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Let the five consecutive intgers be , n, n+1, n+2, n+3, ^ n +4
Summing
n + (n+1) + (n+2) + (n+3) + (n +4) = 170
Hence
5n + 10 = 170
5n = 160
n = 160/5
n = 32
Hence the five consecutive intgers are: 32,33,34,35, & 36
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Three odd consecutive integers whose sum is 176?
First of all, the sum of 3 odd numbers always equals an odd number and 176 is even so this is NOT possible.If you did not know this you could let n be the first odd number, n+2 is the next and n+4 is the third.Add them up and we have n+n+2+n+4=176 or3n+6=176 so3n=170Now you see that 170 is NOT divisible by 3 so ONCE again you see that there is NO solution to this problem. That is to say, there are NOT 3 odd consecutive integers whose sum is 176.
What two integers does the square root of 170 lie between?
13 and 14
What 5 numbers have the mean of 34?
It means the sum of all 5 numbers divided by 5 is 34, which is equivalent to the sum of all five numbers is 170, 5(34). There are many possibilities for 5 numbers to have a sum of 170. It's good if those numbers are close to the mean, 34. For example, 32 + 33 + 34 + 35 + 36 = 170.
What is 850 divided by 5?
170
What is the square root of 170?
13.038404810405297429165943114858
