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Q: What are set of three consecutive integers whose sum is 246?

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2 [ x + (x+1) ] = 246x + (x+1) = 1232x + 1 = 1232x = 122x = 61x+1 = 62ho hum

To solve this, all you have to do is take 246 and add it to 3487. So, 3287 + 246 = 3533.

The LCM is: 49,200.

54

Based on the given information, there is no way to determine the perimeter. Assuming the room is a square, then you could take the square root of 246 (≈15.6843871) and multiply that by 4 (≈ 62.7375484), which would be the perimeter of a square room with this area.

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The numbers are 244, 246 and 248.

244 + 246 + 248 = 738.

The numbers are 245, 246 and 247.

249

2 [ x + (x+1) ] = 246x + (x+1) = 1232x + 1 = 1232x = 122x = 61x+1 = 62ho hum

244+246+248=738

246 and 248.Any even number can be written in the form 2n, for some integer n. The next consecutive integer is 2n + 2. These two numbers added together equal 494:2n + (2n + 2) = 494so4n + 2 = 4944n = 492n = 123so2n = 246 and 2n +2 = 248.

Skylark Three has 246 pages.

It is: 246/305 times 100 = 80.656% rounded to three decimal places

246, 392, and 562

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