They are: 6 and -3
If you mean x2-3x+5 then the answer is none because its discriminant is less than zero
(x + 5)(x - 2)x2 + 3x - 10this is your quadratic equation
x^2+3x-18=0 (x+6)(x-3)=0
x2 + 3x - 18 = 0 (x - 3)(x + 6) = 0 x = 3 or -6
The factors are (x + 6) and (x - 3)
One. It is a double root.
x2 + 3x - 18 = x2 + 6x - 3x - 18 = x(x + 6) - 3(x + 6) = (x + 6)(x - 3)
x2 + 3x - 18 = (x + 6)(x - 3)
Just one. It's at the origin. (0, 0)
We have, f(x) = x2-3x-18 f(x) = x2-3x-18 = x2-6x+3x-18 = x(x-6)+3(x-6) = (x+3)(x-6) Factors are (x-6) and (x+3).
X2 + 3X - 18 = 0What two factors of - 18 add up to 3 ??(X - 3)(X + 6)============so, by the zero sum rule,X = 3X = - 6
If you mean x2-3x+5 then the answer is none because its discriminant is less than zero
3x-1 = 11 3x = 11+1 3x = 12 x = 4 Therefore: x2+2 = 18
(x + 5)(x - 2)x2 + 3x - 10this is your quadratic equation
(x-6)(x+3)
x^2+3x-18=0 (x+6)(x-3)=0
The x-intercepts of the function y = x2 + 3x + 2, can be determine by the quadratic equation which solves x2 + 3x + 2 = 0. In this case A = 1, B = 3, and C = 2. Compute x = (-B ± squareroot (B2 - 4AC)) ÷ 2A x = (-3 ± squareroot (9 - 4)) ÷ 2 x = -1.5 + squareroot (5) ÷ 2 and -1.5 - squareroot (5) ÷ 2 x ~= -0.382 and -2.618