The prime factors are 2x2x2x13
All factors are 1,104,2,52,4,26,8,13
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∙ 12y ago2 and 13
The factors of 104 are: 1, 2, 4, 8, 13, 26, 52, 104.
The factors of 104 are: 1, 2, 4, 8, 13, 26, 52, 104.
2*2*2*13 = 104
the answer is ........ factors are 1,2,3,6,9,18 ; 1x18,2x9,3x6 prime factors are 2x3x3
The Prime factors of 104 are 2 and 13.
The prime factors of 104 are 2x2x2x13.
As a product of its prime factors: 2*3*13 = 78 As a product of its prime factors: 2*2*2*13 = 104 or as 23*13 = 104
The factors of 104 are: 1 2 4 8 13 26 52 104 The prime factors are: 2 x 2 x 2 x 13
2 and 13
They are 2 and 13
2*2*2*13 = 104
The prime factorization of 104 is 2 x 2 x 2 x 13.The prime factorization of 104 is 2 to the third power times 13.2 * 2 * 2 * 132 x 2 x 2 x 13 = 104
No. Any even number (other than 2) is not prime because it is divisible by 2. Factoring 104 presents: 104/2 52/2 26/2 13 104 factors to 2 x 2 x 2 x 13 Since a prime number factors to 1 and itself, 104 cannot be prime.
It is: 2*2*5*7 = 140
Use a factor tree. 104 52,2 26,2,2 13,2,2,2
The factors of 48 are 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48. The factors of 104 are 1, 2, 4, 8, 13, 26, 52, and 104. The largest factor they have in common is 8, so 8 is the greatest common factor. You can also determine the greatest common factor by their prime factors. The prime factors of 48 are 2, 2, 2, 2, and 3. The prime factors of 104 are 2, 2, 2, and 13. The prime factors they have in common are 2, 2, and 2, so the greatest common factor is 2 x 2 x 2 = 8.