The factors of 2700 are 1, 2, 3, 4, 5, 6, 9, 10, 12, 15, 18, 20, 25, 27, 30, 36, 45, 50, 54, 60, 75, 90, 100, 108, 135, 150, 180, 225, 270, 300, 450, 540, 675, 900, 1350, and 2700. The prime factors of 2700 are 2 x 2 x 3 x 3 x 3 x 5 x 5.
to find the number of divisors of number is same as finding number of factors step1:break number into prime components 2700=(3^3)*(2^2)*(5^2) now just take the powers of all prime factors and add 1 to it and multiply (3+1)*(2+1)*(2+1)=36 divisors or factors for 2700
180
All multiples of 2,700 which is an infinite number. The first five are: 2700, 5400, 8100, 10800, 13500.
It would have 17 sides beacause: (n-2)*180=2700 n=7
540
-75 and -36
There are 2700 of them in 2700 pence.
to find the number of divisors of number is same as finding number of factors step1:break number into prime components 2700=(3^3)*(2^2)*(5^2) now just take the powers of all prime factors and add 1 to it and multiply (3+1)*(2+1)*(2+1)=36 divisors or factors for 2700
Yes, because it has more than two factors
5% of 2700= 5% * 2700= 0.05 * 2700= 135
30% of 2700= 30% * 2700= 0.3 * 2700= 810
65% of 2700 = 65% * 2700 = 0.65 * 2700 = 1,755
3% of 2700 = 2700 × 3/100 = 81
2700
No, 2700 is not a perfect cube. A perfect cube is a number that can be expressed as the cube of an integer. The prime factorization of 2700 is (2^2 \times 3^3 \times 5^2), and since not all prime factors have exponents that are multiples of three, it cannot be a perfect cube.
2700 what
27=1% of 2700 Work: 0.01*2700=27