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Furthermore, if the question refers to a linear equation, as I think it might, then there are infinitely many ordered pairs and it would be impossible to answer the question other thatn to give a selection of solutions.
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There are infinitely many ordered pairs. One of these is (0, 0).
(4,1) and (20, y)
Ordered pairs are used in graphing, with the x axis first in the pair. Example: (5,7) (x,y)
The function table will have two columns, one for the x-value and one for the y-value. Form ordered pairs (x,y) by inserting the values from one row of the table.
I am sorry but the question is incomplete. You have not mentioned the ordered pairs and the equation is incomplete as well.
Y is the second number in a set of ordered pairs.
There are infinitely many ordered pairs. One of these is (0, 0).
15
Ordered pairs that have a negative x and a positive y are in the second quadrant.
Put in function form. X = 5 + Y 5 + Y = - X Y = - X - 5 ==================The ordered pairs.
You can write ordered pairs as ratios to determine if two sets of ordered pairs form a linear or non-linear relationship. In a table of x,y values, the ordered pairs are listed as the x value first, then the corresponding y value. Remove from the table and write as a ratio of x over y, (or y over x, if you like). In a linear relationship, all the ratios of x over y, (or y over x) are equivalent.
They are all the pairs you make where (x = any number) and (y = 4).
(4,1) and (20, y)
Ordered pairs are used in graphing, with the x axis first in the pair. Example: (5,7) (x,y)
The equation y = 7x represents a linear relationship where the value of y is always 7 times the value of x. Therefore, all ordered pairs for this equation will have y as a multiple of 7x. For example, when x = 1, y = 7; when x = 2, y = 14; and so on. The ordered pairs for y = 7x will be in the form (x, 7x).
The function table will have two columns, one for the x-value and one for the y-value. Form ordered pairs (x,y) by inserting the values from one row of the table.
I am sorry but the question is incomplete. You have not mentioned the ordered pairs and the equation is incomplete as well.