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2³ , 5 , 7 and 9

because 2³ * 5 * 7 * 9 = 2520

Factor tree:

2520

2 x 1260

2 x 2 x 630

2 x 2 x 2 x 315

2 x 2 x 2 x 3 x 105

2 x 2 x 2 x 3 x 3 x 35

2 x 2 x 2 x 3 x 3 x 5 x 7

The prime factorization of 2520 is 2 x 2 x 2 x 3 x 3 x 5 x 7 or 23 x 32 x 5 x 7.

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Q: What are the prime numbers of 2520 using exponents?
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Related questions

What is the prime factorization of 2520 using exponents?

2^3 x 3^2 x 5^1 x 7^1


How can you write 2520 as the product of prime numbers?

Expressed as a product of its prime factors, 2520 = 23 x 32 x 5 x 7


What are the prime factors of 2520?

2520 = 2 * 2 * 2 * 3 * 3 * 5 * 7


What are prime factors of 2520?

2 * 2 * 2 * 3 * 3 * 5 * 7 = 2520


What is the lowest number that has all the numbers 1-10 as factors?

2520


What numbers can be divisible by all numbers from 1 to 10?

Any one of the infinite set of numbers of the form 2520*k where k is an integer.


What is a common denominator for 9 8 7 and 5?

All those numbers are mutually prime (5 and 7 are prime, full stop), so the least common denominator is 5x7x8x9.


What is 2509 over 2520 simplified to?

Since the numbers 2509 and 2520 share no common positive integer factors, the proper fraction 2509/2520 is already expressed in its simplest form.


What is the smallest number greater than zero that the first four prime numbers as well as the first four composite numbers evenly divide?

Okay I think it is 2520. First 4 prime numbers are; 2 3 5 7 First 4 composites are; 4 6 8 9 I put the composites into there prime factor form. 4=2*2 6=2*3 8=2*2*2 9=3*3 Therefore the prime factor of this number had to have three twos, two threes. It also had to have a 5 and a 7 because of the prime numbers. So the index form was; ?=2*2*2*3*3*5*7 ?=2520


Who number divided by all 123456789 numbers?

2520, for one.


What are two numbers that are divisible by 123456789 and10?

2520 and 5040


What whole number is divisible by the numbers from 1 to 10?

2520