x5 - 2x4 - 24x3 = 0
x3(x2 - 2x - 24) = 0
x3(x2 + 4x - 6x - 24) = 0
x3(x - 6)(x + 4) = 0
x = {-4, 0, 6}
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Yes. In general, two matrices of the same size can be added.
6y(2x4)=
If you mean '2x4' as in 2 times 4- 2x4= 8 3x3= 9 4x2= 8 8-9-8=-19 if you want to divide by x -b/c x doesn't have a set amount- it would be: -19/x
(2 x 4) squared8 squared8x864
2*(4*4*4)=128