2 and 10.
2*10=20
2+10=12
Factors of 20 are 1, 2, 4, 5, 10 and 20. And their sum is 1 + 2 + 4 + 5 + 10 + 20 = 32.
The factor pairs of 200 are (200,1)(100,2)(50,4)(40,5)(25,8)(20,10) None of them have a sum or difference of 20. Factors of 200 that add to 20 are 10 and 10.
20
6, 12, and 20
Let label one of the numbers with x, and the other one with y. So, xy = -240 x + y = 8 y = 8 - x substitute this into the first equation; x(8 - x) = -240 8x - x^2 = - 240 -x^2 + 8x + 240 = 0 or multiplying by -1 both sides; x^2 - 8x - 240 = 0 (x + 12)(x - 20) = 0 x + 12 = 0 or x - 20 = 0 x = -12 or x = 20 So these numbers are -12 and 20. Check: -12 + 20 = 8 (-12)(20) = -240
8 and 12 are factors of 20, 8 + 12 = 20
10 and 2
The two factors of 24 that give you a sum of 20 are 12 and 8.
1 + 2 + 4 = 7
The sum of two numbers between 20-40 is 58. The difference is 12
2, 6 and 12.
20 + 12 = 32 20 x 12 = 240
20
12 and 8
The two numbers are 10 and 2
8and12
10 + 2 = 1210 x 2 = 20