For this explanation, let's assume you have a curve that is parametrically defined by:
x=4t
y=t2+et
An easy way to "eliminate" the parameter and therefore have a function defined by variables x and y is to solve for t using one of the parameterized variables:
x=4t, so t=x/4
This solution for t can be plugged into the other parametrized variable:
y=t2+et and t=x/4, so y=(x/4)2+ex/4
y=x2/16+ex/4
You now have a single-variable function equivalent to the parameterized curve. This method does not always work, but for most general calculus classes (especially Calc I), this is all that you will need to know.
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You put in the answers you got for your variables into one of the equations. If it gives you the correct answer then you solved it, if it's different then either it doesn't work or one of the steps wasn't completed correctly or at all.
There are four steps in an algebraic elimination problem. These steps are: to find a variable with equal or opposite coefficients, if equal then subtract the equations but if opposite then add, solve one variable equation left, and then substitute known variable into other equation and solve. hi
The steps that are taken are many,with errors they often are fraught.But don't feel dismay;keep pluggin' away!With practice is how you are taught.
Step one is by expressing one of the equation into one term that is taking one unknown in the form of other. Step two is replacing the unknown into equation 2. Step 3 is replacing the found unknown into one of initial equations to find the other unknown.
In construction of a stair If 10 inches per step how many steps to go to a story up or about 10 foot 10 feet is 120 inches Slope is 10 inches 10x = 120 That is a linear equation you then solve in your head the answer is 13 steps