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It is a labor remuneration system where a worker's wage is increased proportionality with the number of physical units produce. This system differs from the straight rate labor system in that a worker is not paid a fixed flat rate for every unit of output but his earning per unit produced keeps on increasing as the worker produced more.
Normally there is a different rate for every level of output. Example
for the first 100 units -------------- wage; $10
for the next 101-200 units---------wage; $15
for the next 201-300 units--------- wage; $20
300 units and above----------------- wage; $25
This is a super sweating system that push the workers to their limited best ability as they pursue a higher wage rate.
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Application of differential equation in chemistry?
The rate at which a chemical process occurs is usually best described as a differential equation.
What is differential equations as it relates to algebra?
It is an equation in which one of the terms is the instantaneous rate of change in one variable, with respect to another (ordinary differential equation). Higher order differential equations could contain rates of change in the rates of change (for example, acceleration is the rate of change in the rate of change of displacement with respect to time). There are also partial differential equations in which the rates of change are given in terms of two, or more, variables.
Purpose of differential equations?
Differential equations can be used for many purposes, but ultimately they are simply a way of describing rates of change of variables in an equation relative to each other.Many real world events can be modeled with differential equations.For example, imagine that you are observing a cart rolling down a hill, and can measure it's displacement over time as being d = t2 + 3t + 4. Given that, you can calculate it's velocity at any given moment by taking the derivative of the same equation, as velocity is the rate of change of displacement:d = t2 + 3t + 4v = dd/dt∴ v = 2t + 3Similarly, because acceleration is the rate of change of velocity, you can use the same technique to calculate the rate at which the cart is accelerating:v = 2t + 3a = dv/dt∴ a = 2This is just one simple example of how differential equations can be used, but the number of applications are endless.
What is the unit rate for 2488 parts in eight hours Don't understand?
If you divide the 2488 parts by the 8 hours, then you get information about how many parts are produced every hour - assuming, of course, that this unit rate is constant.
What is the difference between a unit rate and rate?
A rate is something that happens frequently, while a unit rate is an individual digit.
