The sum of 3x plus 2 and -4 plus 3 is 3x+1 if the equation is (3x+2)+(-4+3). If they are two separate questions, 3x+2 remains as itself while -4+3=-1.
2x + 20 = 3x20 = 3X - 2X20 = X
If 3x + 3 = 2x + 6 then 3x - 2x = 6 - 3 x = 3
It is: 3x+10y+5 simplified
If: x+7-4x+1 = -10 Then: 8-3x = -10 And: -3x = -10-8 => -3x = -18 So: x = -18/-3 => x = 6
3-3x
4x + 5 = 3x + 84x-3x + 5 - 5 = 3x - 3x + 8 -5x = 3
3x + 18
I think you mean (3x ± 1)^2 = (3x+1)(3x-1)?
eq: 3x+5=7 =3x=7-5 =3x=2 =x=2/3
If this is algebra then; 3x plus 12x = 15x
Both equations are equal and so: 3x+1 = 2x+3 3x-2x = 3-1 x = 2 and by substituting y = 7
-3x + 10x = 7x3x + 3x = 6x
(14x-2y)+(7x-3y)+(-3x) = 14x-2y+7x-3y-3x =(14+7-3)x-(2+3)y =18x-5y
2x + x = -27 3x = -27 3x/3 = -27/3 x = -9
3x + 7 = -3x 6x = -7 x = -7/6
3x-4=12 Plus 4 both sides 3x-4+4=12+4 3x=16 divide 3 both sides 3x/3=16/3 x=16/3 x= 5.33