In 2-dimensional space, an equality could be represented by a line. A set of equalities would be represented by a set of lines. If these lines intersected at a single point, that point would be the solution to the set of equations.
With inequalities, instead of a line you get a region - one side of the line representing the corresponding equality (or the other). The line, itself, may be included or excluded. Each inequality can be represented by a region and, if these regions overlap, any point within that sub-region is a solution to the system of inequalities.
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Compound inequalities is when there is two inequality signs. You will regularly graph compound inequalities on a number line.
It means that however many different solutions (answers) you have, there will always be more solutions that can be proven, and you can never find them all.
No. At least, it can't have EXACTLY 3 solutions, if that's what you mean. A system of two linear equations in two variables can have:No solutionOne solutionAn infinite number of solutions
Instead of using y = mx + b you use y (inequality sign) mx + b. By inequality sign, I mean symbols like
Your question asks about "each inequalities" which is grammatically impossible since "each" implies singular whereas inequalities implies plural. Consequently it is not clear whether you mean "each inequality" or "each of a set of inequalities". In either case the set is called the feasible region, or the 2-dimensional solution set.