answersLogoWhite

0

What is 10-2n?

User Avatar

Wiki User

โˆ™ 2008-03-29 00:28:14

Best Answer

5=n

User Avatar

Wiki User

โˆ™ 2008-03-29 00:28:14
This answer is:
User Avatar
Study guides

Algebra

20 cards

A polynomial of degree zero is a constant term

The grouping method of factoring can still be used when only some of the terms share a common factor A True B False

The sum or difference of p and q is the of the x-term in the trinomial

A number a power of a variable or a product of the two is a monomial while a polynomial is the of monomials

โžก๏ธ
See all cards
3.79
โ˜†โ˜…โ˜†โ˜…โ˜†โ˜…โ˜†โ˜…โ˜†โ˜…
1456 Reviews

Add your answer:

Earn +20 pts
Q: What is 10-2n?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Algebra
Related questions

Why are all even number digit palindromes divisible by 11?

First, by induction it is shown that 102n-1 ≡ -1 (mod 11) for all natural numbers n (that is, all odd powers of 10 are one less than a multiple of 11.) i) When n = 1, then we have 102(1)-1 = 10, which is certainly congruent to -1 (mod 11). ii) Assume 102n-1 ≡ -1 (mod 11). Then, 102(n+1)-1 = 102n+2-1 = 102×102n-1 102 ≡ 1 (mod 11) and 102n-1 ≡ -1 (mod 11), so their product, 102×102n-1, is congruent to 1×(-1) = -1 (mod 11). Now that it is established that 10, 1000, 100000, ... are congruent to -1 (mod 11), it is clear that 11, 1001, 100001, ... are divisible by 11. Therefore, all integer multiples of these numbers are also divisible by 11. A palindrome containing an even number of digits may always be written as a sum of multiples of such numbers. The general form of such a palindrome, where all the As are integers between 0 and 9 inclusive, is A0 100 + A1 101 + ... + An 10n + An 10n+1 + ... + A1 102n + A0 102n+1 which may be rewritten as A0 (100 + 102n+1) + A1 (101 + 102n) + ... + An (10n + 10n+1) and again as 100 A0 (1 + 102n+1) + 101 A1 (1 + 102n-1) + ... + 10n An (1 + 101) Each of the factors in parentheses is one more than an odd power of 10, and is hence divisible by 11. Therefore, each term, the product of one such factor with two integers, is divisible by 11. Finally, the sum of terms divisible by 11 is itself divisible by 11. QED


How is 27 x 23n plus 17 x 102n divisible by 11?

27*23n+17*102n27*23=62117*102=1734621+1734=23552355nFactors of 2355n2355n/n=23552355/5=471471/3=1572355n=n*5*3*15711 is NOT a factor


The sum of two consecutive odd numbers is 44 What is the smaller number?

Calculation by IntuitionFor any odd integer n, the consecutive odd number is n+2n + (n+2) = 442n = 42n = 21, and the second number is 23--------Calculation of Integers methodFor any integer n, the first odd number is 2n + 1, and the second number is 2n + 3.[2n + 1] + [2n + 3] = 444n + 4 = 44 subtract 4 to both sides4n = 40 divide by 4 to both sidesn = 102n + 1 = 2(10) + 1 = 20 + 1 = 21Thus the smallest number is 21.


People also asked