3000. JHC!
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-37
1 x 30, 2 x 15, 3 x 10, 5 x 6, 6 x 5, 10 x 3, 15 x 2, 30 x 1.
Let the numbers be x and y, then x + y = 60 (which yields y = 60 - x) xy = 1600 (replace y with 60 - x) x(60 - x) = 1600 60x - x2 = 1600 (multiply by -1 to both sides) x2 - 60x = -1600 (add 302 to both sides to complete the square) x2 - 60x + 302 = -1600 + 900 (x - 30)2 = -700 (take the square root of both sides) x - 30 = ± √-700 (add 30 to both sides and write -700 = (100)(7)(-1)) x = 30 ± (√100)(√7)(√-1) x = 30 ± (10√7)i So, x = 30 + (10√7)i or x = 30 - (10√7)i thus, y = 60 - [30 + (10√7)i] or y = 60 - [30 - (10√7)i ] y = 30 - (10√7)i or y = 30 + (10√7)i Therefore, [30 + (10√7)i] + [30 - (10√7)i] = 60 [30 + (10√7)i] [30 - (10√7)i] = 1600 Check:
10 x 3 = 30
x^2+7x-30 = (x-3)(x+10)