"1 glance 2 3 glance" is a play on words that sounds like "once, twice, three times." It's a clever way to say something happened multiple times, like taking a quick look or glance. So, in a nutshell, it's basically saying you looked three times in a snazzy way.
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1. Glance
2.
3. Glance
Riddle..
Answer: Without a Second Glance
Half of 3 means 3 divided by 2 or 3 multipled by 1/2. Thus 1/2 X 3 = 3/2.
Points: (-1, 2) and (3, 3) Slope: 2-3/-1-3 = 1/4
1=(4-3)÷(2-1)2=(4+2)-(3+1)3=3×2-4+14=4÷2+3-15=12-(3+4)6=(3×4)×1÷27=1+(3×4)÷28=4+2-1+39=41-3210=(1×4)+(3×2)11=42-3112=(4×3)×(2-1)13=12-3+414=(3×4)×1+215=(3×4)+1+216=2(3+4+1)17=3(4+2)-118=32-1419=14+3+220=4(2+3×1)21=(1+2)×(3+4)22=34-1223=4(3×2)-124=1×3×4×225=(4+1)×(3+2)26=2(4×3+1)27=1×3+2428=4(2×3+1)29=1+32-430=2(1+4)×331=34-1-232=2(1+3)×433=21+3×434=34(2-1)35=4+32-136=4(2+1)×337=14+2338=42-1-339=42-(3×1)40=43-1-241=43-(2×1)42=43-2+143=43(2-1)44=2+3(14)45=12×4-346=41+2+347=41+(3×2)48=24(3-1)49=I Don't Know50=13×4-2
Points: (-2, 3) and (1, 1) Slope: -2/3
x + y = 1xy = 1y = 1 - xx(1 - x) = 1x - x^2 = 1-x^2 + x - 1 = 0 or multiplying all terms by -1;(-x^2)(-1) + (x)(-1) - (1)(-1) = 0x^2 - x + 1 = 0The roots are complex numbers. Use the quadratic formula and find them:a = 1, b = -1, and c = 1x = [-b + square root of (b^2 - (4)(a)(c)]/2a orx = [-b - square root of (b^2 - (4)(a)(c)]/2aSox = [-(-1) + square root of ((-1)^2 - (4)(1)(1)]/2(1)x = [1 + square root of (1 - 4]/2x = [1 + square root of (- 3)]/2 orx = [1 + square root of (-1 )(3)]/2; substitute (-1) = i^2;x = [1 + square root of (i^2 )(3)]/2x = [1 + (square root of 3)i]/2x = 1/2 + [i(square root of 3]/2 andx = 1/2 - [i(square root of 3)]/2Since we have two values for x, we will find also two values for yy = 1 - xy = 1 - [1/2 + (i(square root of 3))/2]y = 1 - 1/2 - [i(square root of 3)]/2y = 1/2 - [i(square root of 3)]/2 andy = 1 - [1/2 - (i(square root of 3))/2)]y = 1 - 1/2 + [i(square root of 3))/2]y = 1/2 + [i(square root of 3)]/2Thus, these numbers are:1. x = 1/2 + [i(square root of 3)]/2 and y = 1/2 - [i(square root of 3)]/22. x = 1/2 - [i(square root of 3)]/2 and y = 1/2 + [i(square root of 3)]/2Let's check this:x + y = 11/2 + [i(square root of 3)]/2 +1/2 - [i(square root of 3)]/2 = 1/2 + 1/2 = 1xy = 1[1/2 + [i(square root of 3)]/2] [1/2 - [i(square root of 3)]/2]= (1/2)(1/2) -(1/2)[i(square root of 3)]/2] + [i(square root of 3)]/2](1/2) - [i(square root of 3)]/2] [i(square root of 3)]/2]= 1/4 - [i(square root of 3)]/4 + [i(square root of 3)]/4 - (3i^2)/4; substitute ( i^2)=-1:= 1/4 - [(3)(-1)]/4= 1/4 + 3/4= 4/4=1In the same way we check and two other values of x and y.
1. casually glance at his lips 2. be super flirty! 3. be-you-tiful
1. Peer 2. Glance
Home Improvement - 1991 Overactive Glance 2-3 was released on: USA: 30 September 1992 Hungary: 20 May 2009
1. Peek 2. Glimpse
1. You are going to have to get out of your comfort zone 2. Find a girl you like 3. Talk about what she likes 4. Stare/glance (Not creepily, flirtaciously) *If you are super shy it will be tough
Because the cube of a positive number is positive and the cube of a negative number is negative.-------------------------------------------------------------------------------------------------------------------------------Every number has THREE cube roots. However, (at least) two of the three are complex numbers.For example, the cube roots of 8 are 2, (-1 + √3 i) and (-1 - √3 i) with i² = -1:2³ = 2 × 2 × 2 = 8(-1 + √3 i)³ = (-1 + √3 i)(-1 + √3 i)(-1 + √3 i)= (-1 + √3 i)((-1)² - 2√3 i + 3i²)= (-1 + √3 i)(1 - 2√3 i -3)= (-1 + √3 i)(-2 - 2√3 i)= (-1 + √3 i)(-1 - √3 i)2= ((-1)² - 3i²)2= (1 + 3)2= 4 × 2 = 8(-1 - √3 i)³ = (-1 - √3 i)(-1 - √3 i)(-1 - √3 i)= (-1 - √3 i)((-1)² + 2√3 i + 3i²)= (-1 - √3 i)(1 + 2√3 i -3)= (-1 - √3 i)(-2 + 2√3 i)= (-1 - √3 i)(-1 + √3 i)2= ((-1)² - 3i²)2= (1 + 3)2= 4 × 2 = 8
4
1 1 1 2 1 3 1 4 2 1 2 2 2 3 2 4 3 1 3 2 3 3 3 4 4 1 4 2 4 3 4 4
434
A huge number. 0 + 1 + 2 = 3 0 + 2 + 1 = 3 1 + 0 + 2 = 3 1 + 2 + 0 = 3 2 + 0 + 1 = 3 2 + 1 + 0 = 3 -0 + 1 + 2 = 3 -0 + 2 + 1 = 3 1 - 0 + 2 = 31 + 2 - 0 = 32 - 0 + 1 = 32 + 1 - 0 = 3 0 - 1 + 3 = 2 0 + 3 - 1 = 2 -1 + 0 + 3 = 2 -1 + 3 + 0 = 2 3 + 0 - 1 = 2 3 - 1 + 0 = 2 -0 - 1 + 3 = 2-0 + 3 - 1 = 2-1 - 0 + 3 = 2-1 + 3 - 0 = 23 - 0 - 1 = 23 - 1 - 0 = 2 0 - 2 + 3 = 1 0 + 3 - 2 = 1 -2 + 0 + 3 = 1 -2 + 3 + 0 = 1 3 + 0 - 2 = 1 3 - 2 + 0 = 1 -0 - 2 + 3 = 1-0 + 3 - 2 = 1-2 - 0 + 3 = 1-2 + 3 - 0 = 13 - 0 - 2 = 13 - 2 - 0 = 1 1 + 2 - 3 = 0 1 - 3 + 2 = 0 2 + 1 - 3 = 0 2 - 3 + 1 = 0 -3 + 1 + 2 = 0 -3 + 2 + 1 = 0 For each of these equations there is a counterpart in which all signs have been switched. For example 0 + 1 + 2 = 3 gives -0 - 1 - 2 = -3and so on. Now, all of the above equations has three numbers on the left and one on the right. Each can be converted to others with two numbers on each side. For example:the equation 0 + 1 + 2 = 3 gives rise to0 + 1 = 3 - 20 + 1 = -2 + 30 + 2 = 3 - 10 + 2 = -1 + 31 + 2 = 3 - 01 + 2 = -0 + 3-0 + 1 = 3 - 2-0 + 1 = -2 + 3-0 + 2 = 3 - 1-0 + 2 = -1 + 31 + 2 = 3 + 01 + 2 = +0 + 3 As you can see, the number of equations is huge!
1/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/21/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/21/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/21/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/2
1 1/3 × 2/3 = (1×3+1)/3 × 2/3 = 4/3 × 2/3 = (4×2)/(3×3) = 8/9