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1. Glance
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3. Glance
Riddle..
Answer: Without a Second Glance
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∙ 13y ago
Reese Galloway
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What is half of three in fraction form?
Half of 3 means 3 divided by 2 or 3 multipled by 1/2. Thus 1/2 X 3 = 3/2.
What is the slope of the line that contains the points -1 2 and 3 3?
Points: (-1, 2) and (3, 3) Slope: 2-3/-1-3 = 1/4
How do you get the numbers one through fifty using only the digits 1234?
1=(4-3)÷(2-1)2=(4+2)-(3+1)3=3×2-4+14=4÷2+3-15=12-(3+4)6=(3×4)×1÷27=1+(3×4)÷28=4+2-1+39=41-3210=(1×4)+(3×2)11=42-3112=(4×3)×(2-1)13=12-3+414=(3×4)×1+215=(3×4)+1+216=2(3+4+1)17=3(4+2)-118=32-1419=14+3+220=4(2+3×1)21=(1+2)×(3+4)22=34-1223=4(3×2)-124=1×3×4×225=(4+1)×(3+2)26=2(4×3+1)27=1×3+2428=4(2×3+1)29=1+32-430=2(1+4)×331=34-1-232=2(1+3)×433=21+3×434=34(2-1)35=4+32-136=4(2+1)×337=14+2338=42-1-339=42-(3×1)40=43-1-241=43-(2×1)42=43-2+143=43(2-1)44=2+3(14)45=12×4-346=41+2+347=41+(3×2)48=24(3-1)49=I Don't Know50=13×4-2
What is the slope of the line through (-2 3) and (1 1)?
Points: (-2, 3) and (1, 1) Slope: -2/3
Find the two numbers whose product is 1 and whose sum is 1?
x + y = 1xy = 1y = 1 - xx(1 - x) = 1x - x^2 = 1-x^2 + x - 1 = 0 or multiplying all terms by -1;(-x^2)(-1) + (x)(-1) - (1)(-1) = 0x^2 - x + 1 = 0The roots are complex numbers. Use the quadratic formula and find them:a = 1, b = -1, and c = 1x = [-b + square root of (b^2 - (4)(a)(c)]/2a orx = [-b - square root of (b^2 - (4)(a)(c)]/2aSox = [-(-1) + square root of ((-1)^2 - (4)(1)(1)]/2(1)x = [1 + square root of (1 - 4]/2x = [1 + square root of (- 3)]/2 orx = [1 + square root of (-1 )(3)]/2; substitute (-1) = i^2;x = [1 + square root of (i^2 )(3)]/2x = [1 + (square root of 3)i]/2x = 1/2 + [i(square root of 3]/2 andx = 1/2 - [i(square root of 3)]/2Since we have two values for x, we will find also two values for yy = 1 - xy = 1 - [1/2 + (i(square root of 3))/2]y = 1 - 1/2 - [i(square root of 3)]/2y = 1/2 - [i(square root of 3)]/2 andy = 1 - [1/2 - (i(square root of 3))/2)]y = 1 - 1/2 + [i(square root of 3))/2]y = 1/2 + [i(square root of 3)]/2Thus, these numbers are:1. x = 1/2 + [i(square root of 3)]/2 and y = 1/2 - [i(square root of 3)]/22. x = 1/2 - [i(square root of 3)]/2 and y = 1/2 + [i(square root of 3)]/2Let's check this:x + y = 11/2 + [i(square root of 3)]/2 +1/2 - [i(square root of 3)]/2 = 1/2 + 1/2 = 1xy = 1[1/2 + [i(square root of 3)]/2] [1/2 - [i(square root of 3)]/2]= (1/2)(1/2) -(1/2)[i(square root of 3)]/2] + [i(square root of 3)]/2](1/2) - [i(square root of 3)]/2] [i(square root of 3)]/2]= 1/4 - [i(square root of 3)]/4 + [i(square root of 3)]/4 - (3i^2)/4; substitute ( i^2)=-1:= 1/4 - [(3)(-1)]/4= 1/4 + 3/4= 4/4=1In the same way we check and two other values of x and y.
How do you get him to kiss you first?
1. casually glance at his lips 2. be super flirty! 3. be-you-tiful
What word is a synonym for word peeked?
1. Peer 2. Glance
What are the release dates for Home Improvement - 1991 Overactive Glance 2-3?
Home Improvement - 1991 Overactive Glance 2-3 was released on: USA: 30 September 1992 Hungary: 20 May 2009
What are two words tha mean quick glance?
1. Peek 2. Glimpse
Why does a cube root only have one value?
Because the cube of a positive number is positive and the cube of a negative number is negative.-------------------------------------------------------------------------------------------------------------------------------Every number has THREE cube roots. However, (at least) two of the three are complex numbers.For example, the cube roots of 8 are 2, (-1 + √3 i) and (-1 - √3 i) with i² = -1:2³ = 2 × 2 × 2 = 8(-1 + √3 i)³ = (-1 + √3 i)(-1 + √3 i)(-1 + √3 i)= (-1 + √3 i)((-1)² - 2√3 i + 3i²)= (-1 + √3 i)(1 - 2√3 i -3)= (-1 + √3 i)(-2 - 2√3 i)= (-1 + √3 i)(-1 - √3 i)2= ((-1)² - 3i²)2= (1 + 3)2= 4 × 2 = 8(-1 - √3 i)³ = (-1 - √3 i)(-1 - √3 i)(-1 - √3 i)= (-1 - √3 i)((-1)² + 2√3 i + 3i²)= (-1 - √3 i)(1 + 2√3 i -3)= (-1 - √3 i)(-2 + 2√3 i)= (-1 - √3 i)(-1 + √3 i)2= ((-1)² - 3i²)2= (1 + 3)2= 4 × 2 = 8
How many different combinations can you make with 2 4s 1 3 and 1 2?
1 1 1 2 1 3 1 4 2 1 2 2 2 3 2 4 3 1 3 2 3 3 3 4 4 1 4 2 4 3 4 4
What are the next three numbers in the given series 1 1 2 1 2 2 3 1 2 2 3 2 3 3 4 1 2 2 3 2 3 3?
434
How many different equations can be made with the numbers 0123?
A huge number. 0 + 1 + 2 = 3 0 + 2 + 1 = 3 1 + 0 + 2 = 3 1 + 2 + 0 = 3 2 + 0 + 1 = 3 2 + 1 + 0 = 3 -0 + 1 + 2 = 3 -0 + 2 + 1 = 3 1 - 0 + 2 = 31 + 2 - 0 = 32 - 0 + 1 = 32 + 1 - 0 = 3 0 - 1 + 3 = 2 0 + 3 - 1 = 2 -1 + 0 + 3 = 2 -1 + 3 + 0 = 2 3 + 0 - 1 = 2 3 - 1 + 0 = 2 -0 - 1 + 3 = 2-0 + 3 - 1 = 2-1 - 0 + 3 = 2-1 + 3 - 0 = 23 - 0 - 1 = 23 - 1 - 0 = 2 0 - 2 + 3 = 1 0 + 3 - 2 = 1 -2 + 0 + 3 = 1 -2 + 3 + 0 = 1 3 + 0 - 2 = 1 3 - 2 + 0 = 1 -0 - 2 + 3 = 1-0 + 3 - 2 = 1-2 - 0 + 3 = 1-2 + 3 - 0 = 13 - 0 - 2 = 13 - 2 - 0 = 1 1 + 2 - 3 = 0 1 - 3 + 2 = 0 2 + 1 - 3 = 0 2 - 3 + 1 = 0 -3 + 1 + 2 = 0 -3 + 2 + 1 = 0 For each of these equations there is a counterpart in which all signs have been switched. For example 0 + 1 + 2 = 3 gives -0 - 1 - 2 = -3and so on. Now, all of the above equations has three numbers on the left and one on the right. Each can be converted to others with two numbers on each side. For example:the equation 0 + 1 + 2 = 3 gives rise to0 + 1 = 3 - 20 + 1 = -2 + 30 + 2 = 3 - 10 + 2 = -1 + 31 + 2 = 3 - 01 + 2 = -0 + 3-0 + 1 = 3 - 2-0 + 1 = -2 + 3-0 + 2 = 3 - 1-0 + 2 = -1 + 31 + 2 = 3 + 01 + 2 = +0 + 3 As you can see, the number of equations is huge!
What is 1 half add 1 and a half times by 2?
1/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/21/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/21/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/21/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/2
Adding two cube's equal to 9 i want two answers?
1^3 + 2^3 = 1 + 8 = 9 2^3 + 1^3 = 8 + 1 = 9 There is also: 1^3 + (-1 + i√3)^3 = 9 1^3 + (-1 - i√3)^3 = 9 (-1/2 + i√3/2)^3 + 2^3 = 9 (-1/2 - i√3/2)^3 + 2^3 = 9
What is 2 to the 1 to the 3?
2^1^3=2 (2^1)^3=6
How do you get the answer 7 using only numbers -4-3-2-1?
[(-4) + (-3)]*[(-2 - (-1)] = (-4 -3)*(-2 + 1) = -7*-1 = +7[(-4) + (-3)]*[(-2 - (-1)] = (-4 -3)*(-2 + 1) = -7*-1 = +7[(-4) + (-3)]*[(-2 - (-1)] = (-4 -3)*(-2 + 1) = -7*-1 = +7[(-4) + (-3)]*[(-2 - (-1)] = (-4 -3)*(-2 + 1) = -7*-1 = +7
