There are 3 ft in a yd ...[(9 x 3 = 27) + 1] - [(4 x 3 = 12) + 2] = (28 - 14) = 14 ft OR 4 yd 2 ft
Area = side^2 side = √121 = 11 ft Perimeter = 4 x side = 4 x 11 = 44 ft.
It could be 1 x 300 ft. It could be 2 x 150 ft. It could be 3 x 100 ft. It could be 4 x 75 ft. It could be 5 x 60 ft. It could be 6 x 50 ft. It could be 10 x 30 ft. It could be 12 x 25 ft. It could be 15 x 20 ft. . . . etc. There are an infinite number of things it could be. The area doesn't tell you the dimensions.
Sqrt 800 ft ie sqrt 2 x sqrt 4 x sqrt 100 = 20 root2 ft, just over 28' 3.4"
Easy.Rectangle #1: 2-ft x 4-ftPerimeter = 12-ftArea = 8 square ftRectangle #2: 1-ft x 8-ftPerimeter = 18-ft.Area = 8 square ft
3.14 x 4 ----- 12.56 2x2=4
Surface area = 2 x (length x width + width x depth + depth x length) = 2 x (2 ft x 4 ft + 4 ft x 6 ft + 6 ft x 2 ft) = 2 x (8 sq ft + 24 sq ft + 12 sq ft) = 2 x 44 sq ft = 88 sq ft
6 ft x 4 ft x 4 in =6 ft x 4 ft x 1/3 ft = 8 cubic ft.6 ft x 4 ft x 4 in =6 ft x 4 ft x 1/3 ft = 8 cubic ft.6 ft x 4 ft x 4 in =6 ft x 4 ft x 1/3 ft = 8 cubic ft.6 ft x 4 ft x 4 in =6 ft x 4 ft x 1/3 ft = 8 cubic ft.
6 x 5 x 4 and 7 x 6 x 4 qualify. 6 x 2 x 3 and 8 x 4 x 3 do not.
8 tiles
Since volume = length x width x height, the volume of the shipping container would be equal to 6ft x 4 ft x 2 ft = 48 ft3 .
64 cubic feet
16 cub ft.
No.
Possible dimensions for a rectangular prism with a volume of 60 cubic feet could be 3 ft x 4 ft x 5 ft, or 2 ft x 5 ft x 6 ft, or 1 ft x 6 ft x 10 ft. There are multiple combinations of dimensions that can result in a volume of 60 cubic feet for a rectangular prism.
4 ft circle by 15 ft long, (4/2)2 x pi x 15 = 188.5 cu ft 188.5 x 35.315 = 6,656.658 litres
2 ft x 2 ft x 4 ft is equivalent to approximately 60.96 cm x 60.96 cm x 121.9 cm