Yes, 2/5 * 7/8 * 5/2 = 35/40. If you multiply, the solution is 70/80, which reduces to 35/40, which can be reduced further to 7/8
16/35.
The answer is 7
5 over 7 is greater than 3 over five. You have to find a common denominator. The common denominator is 35 so 5 over 7 would become 25 over 35 and 3 over 5 would become 21 over 35. 25/35 > 21/35 = 5/7 > 3/5
2x+5x=35 2+5(x)=35 7(x)=35 7*(5)=35 35=35
Yes, 2/5 * 7/8 * 5/2 = 35/40. If you multiply, the solution is 70/80, which reduces to 35/40, which can be reduced further to 7/8
6/35
= (3/5) x (2/7) = 6/35 = 0.17143
2/5 * 4/7 just multiply through = 8/35
the biggest number that can go into both 10 and 35 is 5. so 5 goes into 10, 2 times and 5 goes into 35, 7 times so the answer is 2/7
1768 over 35 or 50.52
2/5 + 2/7 = 24/35 2/5 + 2/7 =(2/5 * 7/7) + (2/7 * 5/5) =14/35 + 10/35 =24/35
5/7 x 7/10 = 35/70 = 1/2 1/2 x 5/21 = 5/42
(3/7)/(15/2)=(3/7) times (2/15) = 6/105 = 2/35
1/5 = 7/35 2/7 = 10/35 7/35 + 10/35 = 17/35
35 = 5 times 7 35 =7 times 5 35 = 1 times 35 35 = 35 times 1 These are all the ways to write 35 as the product of positive integers, However, 35 = (-5) times (-7) and 35 = 1/2 times 70 and there infinitely many more such products..
35 multiplied by 2/10 is 7.