2a - a = a
y=mx+b A=xy; A=(pi)r^2; V=xyh; (-b= or - (b^2-4ac)^1/2)/2a ( actually read as negative b plus or minus the square root of b squared minus four ac, all divided by 2a....quadratic formula) This should get you, if you need more or this is not what you were looking for, let me know.
4a
2a - 5a = -3a
9a +8 -2a -3 -5a = 2a +5
Using the quadratic formula-- ((negative b plus or minus the square root of b squared minus 4ac) divided by (2a)) you'll want to google that so you can see it in numerical form. a, b, and c are the coefficiants of your three terms ( 2 is a, -5 is b, and 2 is c) The answer is (x-2)(2x-1).
2a-5
2a+5
since a=1a, 3a-1a=2a
2a
-2a - 4 = -16.8 -2a = -12.8 a = -12.8/-2 a = 6.4
2
-16A
6a to the second power minus 8ab + 2a
2a+6b
(a - 2b)(2a - b)
2a + 11a - 5a = 8a
(2a - 5). Take the value of a. Double it to get 2a Take away (subtract 5) to get 2a - 5