Remember the eqution and comit to memory C = 2pir or C = pi d Where 'C' is the circumference 'r' is the radius 'd' is the diamter. and 'pi' is the constant of proportion of circles at 3.141592.... usually approximated to 3.14 e.g. If the radius is 5 Then C = 2 * 3.14 * 5 C = 10*3.14 C = 31.4
circumference equal two times 'pi' times radius. It is written algebraically as C = 2pir Since 2r = d (diameter) Then C = pi*d Also the area (A) of a circle is A = pi*r^(2) 'pi' is the constant of proportion of circles. NB For school work pi = 3.14 or pi = 3.1416 or pi = 22/7
There are two forms of energy stored in atoms and molecules, scalar or Potential energy -vh/2pir = -vp and vector energy cP=cmV Momentum energy. The Total stored energy is W = -vh/2pir + cmV = -vh/2pir + cP = [-vh/2pir, cP].
Diameter=2piR
There are two forms of energy stored in atoms and molecules, scalar or Potential energy -vh/2pir = -vp and vector energy cP=cmV Momentum energy. The Total stored energy is W = -vh/2pir + cmV = -vh/2pir + cP = [-vh/2pir, cP].
C = PI Times Diameter = 2PIr
The arc is one quarter of a circle so is 2pir, the other components of the quarter circle are the two radii, so perimeter is 2r+2pir = 2r(1+pi)
The distance around the whole circle. The equation is piD or 2pir
C=2Pir, since r is 8. the answer would be 16pi.
circumference equal 2*pi*r(radius) C=2PiR
2pir pi = 3.1416 r = radius = 1/2 diameter
Circumference=2Pir so 64 is Pixr and the radius is 64/Pi
C = 2pir (substitute 40pi cm for C) 40pi cm = 2pir (divide by 2pi to both sides) 20 cm = r = 200 mm (since 1 cm = 10 mm)
S.A.(Cyl) = 2pir*h This is for the circular (round) face. Then add the area of the two circular ends 2A = 2pir^(2) Hence for the whole cylinder including the circular ends. S.A. = 2pirh + 2pir^(2) Factor S.A. = 2pir(h + r) So you needs to know the radius(r) and cylinder(length)(h). The units will be squared (units^(2)). An example R = 2 cm h = 20 cm Hence SA = 23.142(2 + 20) SA= 23.142(22) SA = 3.14 (88) SA = 276.32 cm^(2).