3x = 7-4x 3x+4x = 7 7x = 7 x = 1
12x2 - 7x + 1 = 12x2 - 4x - 3x + 1 = 4x(3x - 1) - 1(3x - 1) = (3x - 1)(4x - 1)
3x = 7 - 4x 3x + 4x = 7 - 4x + 4x 7x = 7 7x/7 = 7/7 x = 1
x = -½
(2, 1)
4x=3x+1 => (4x-3x)=1 => x=1 therefore the value of x is 1.
4x+6-7x+9=18-3x+15=18-3x=3x=-1
-((4x + 1)(x - 1))
(2, 7)
4x + 8 = 3x +1subtract 3x from both sidesx + 8 = 1subtract 8 from both sidesx = -7
(3x + 1)(4x - 1)(x - 2)
5x-3x+x+8 = 2x+1+x+x 3x+8 = 4x+1 3x-4x = 1-8 -x = -7 x=7 Hope that helps.
The answer to 3 times 3x-6-3 time 1+4x equals -45. This is a math problem.
You need to organise your question properly. 3x+2y=4 4x + 3y= 7? Is 4 4x = 44x or 4-4x or 4+4x How can there be 2 equal signs in 1 equation?
3x = 7-4x 3x+4x = 7 7x = 7 x = 1
x + 3x - 10 = 5 - 4 4x - 10 = 1 4x = 1 + 10 x = 11/4
combine like terms. 3x+1+4x-5=31 3x+4x=7x 7x+1-5=31 1-5=-4 7x-4=31 then solve it 7x=35 x=5